The arc length of the semicircle is 5π units
<h3>Calculating length of an arc</h3>
From the question, we are to calculate the arc length of the semicircle
Arc length of a semicircle = 1/2 the circumference of the circle
∴ Arc length of a semicircle = 1/2 × 2πr
Arc length of a semicircle = πr
Where r is the radius
From the given information,
r = 5
∴ Arc length of the semicircle = 5 × π
Arc length of the semicircle = 5π units
Hence, the arc length of the semicircle is 5π units
Learn more on Calculating length of an arc here: brainly.com/question/16552139
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(a)
We can see that
this is a straight line
and this is the graph of velocity
we know that
acceleration is the derivative of velocity
so, slope of curve of velocity is acceleration
so, we will find slope of this line
We can select any two points
(0,4) and (5,7)
we can use slope formula
now, we can plug points
we know that slope of line is always constant irrespective of any value of t
so, acceleration will always be same irrespective of any value of t
so, we will get acceleration
............Answer
(b)
we can see that acceleration is constant
and we know that
derivative of constant is always 0
so, instantaneous rate of acceleration at t=10s is 0........Answer
Answer:
The second graph near the bottom with a Y-intercept of -1
I think the error is that you did not divide 6 by 2 first because you are supposed to so you would get 3, then you do 1 times 3 which is 3, then you have 3 plus 3 left which would be 6. i’m hoping this is right and that it helps you
False, they could have different slopes.
