Answer:
Domain : {x | all real numbers} ; Range: {y | y > 0}
Step-by-step explanation:
The function can be written as :
![f(x)=\sqrt[\frac{2}{3}]{108^{2\cdot x}}\\\\\implies f(x)=(108)^{(\frac{3}{2})^{2\cdot x}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5Cfrac%7B2%7D%7B3%7D%5D%7B108%5E%7B2%5Ccdot%20x%7D%7D%5C%5C%5C%5C%5Cimplies%20f%28x%29%3D%28108%29%5E%7B%28%5Cfrac%7B3%7D%7B2%7D%29%5E%7B2%5Ccdot%20x%7D%7D)
Now, since x is exponent so it can take any real values. So, its domain of f(x) is all real numbers
But value of f(x) can not be less than 1 because for x = 0 the value of f(x) is 1 and also for any values of x, the value of f(x) can never be less than 1
So, Range of f(x) is all real numbers greater than 0
Hence, Domain and Range of f(x) is given by :
Domain : {x | all real numbers} ;
Range: {y | y > 0}
So for order of operations you start inside the parentheses and in order to add the insides you will need a common denominator which would be 15 on the bottom. So for 2/5 it would be 6/15 and for 11/3 would be 55/15 and then added together it would be 61/15. so then you would multiply and get 15(61/15). the 15 in the numerator will cancel with the denominator leaving only 61 and then the final step would be adding the 3 to 61 and the final answer will be 64
More, a kilogram is 1000x the mass of a gram
Answer:
5 years
Step-by-step explanation:
Principal Amount to be paid=$4500
Interest rate = 2%
Number if Times compounded= number of years
Number of years = x
Among total= $5010
A= p(1+r/n)^(nt)
But n= t =x
A= p(1+r/x)^(x²)
5010=4500(1+0.02/x)^(x²)
5010/4500 = (1+0.02/x)^(x²)
1.11333=( 1+0.02/x)^(x²)
Using trial and error method the number of years maximum to give approximately $5010 is 5 years
