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docker41 [41]
3 years ago
7

HELP PLZ NEED HELP SHOW WORK TOO

Mathematics
1 answer:
monitta3 years ago
5 0
15.        3x - 2y = -2
      3x - 3x - 2y = -3x - 2
                   -2y = -3x - 2
                    -2         -2
                       y = 1.5x + 1

y - y₁ = m(x - x₁)
 y - 3 = ⁻²/₃(x - (-2))
 y - 3 = ⁻²/₃(x + 2)
 y - 3 = ²/₃(x) - ²/₃(2)
 y - 3 = ⁻²/₃x - 1¹/₃
   + 3            + 3
       y = ⁻²/₃x + 1²/₃

16. 230 = 0.2s + 150
    - 150             - 150
        80 = 0.2s
        0.2    0.2
      400 = s

17. y = 2x + 2
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What is the solution to the equation 93x ≈ 7?
s344n2d4d5 [400]
Well, I do not know if you mean 93x = 7 or 9^3x = 7.
So, I will provide the solution for both cases.

In case of 93x = 7:
This case is simple, all you have to do is isolate the x. You need to get rid of the coefficient which is 93. You can simply do this by dividing both sides of the equation by 93 as follows:
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In case of 9^3x = 7:
Now, we need to get rid of the power. The only function that can do this is the log function.
So, we will start by taking log base 10 for both sides of the equation as follows:
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This will give:
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Now, the final step is to isolate the x as we did before. To do this, we will need to get rid of 3log(9). This can be done by dividing both sides of the equation by 3log(9) as follows:
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This will give us:
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Hope this helps :)
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4 years ago
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