Question

FAST!! Evaluate tan60/cos45 √6 √3/2 √2/3 1√6

Answer 1

Answer:

$\frac{\tan 60\degree}{\cos45 \degree}= \sqrt{6}$

Step-by-step explanation:

We want to evaluate

$\frac{\tan 60\degree}{\cos45 \degree}$

We use special angles or the unit circle to obtain;

$\frac{\tan 60\degree}{\cos45 \degree}=\frac{\sqrt{3}}{\frac{\sqrt{2}}{2}}$

This implies that;

$\frac{\tan 60\degree}{\cos45 \degree}=\sqrt{3}\div \frac{\sqrt{2}}{2}$

$\frac{\tan 60\degree}{\cos45 \degree}=\sqrt{3}\times \sqrt{2}$

$\frac{\tan 60\degree}{\cos45 \degree}= \sqrt{6}$

Answer 2

Answer:

$\sqrt{6}$.

Step-by-step explanation:

$\frac{tan(60)}{cos(45)}$

$= \frac{\frac{sin(60)}{cos(60)}}{cos(45)}$

$= \frac{sin(60)}{cos(60)*cos(45)}$

$= \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}*\frac{\sqrt{2}}{2}}$

$= \frac{\frac{\sqrt{3}}{2}}{\frac{\sqrt{2}}{4}}$

$= \frac{4\sqrt{3}}{2\sqrt{2}}$

$= \frac{2\sqrt{3}}{\sqrt{2}}$

$= \frac{2\sqrt{3}\sqrt{2}}{2}$

$=\sqrt{3}\sqrt{2}$

$=\sqrt{6}$.