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LenKa [72]
3 years ago
13

which equation is the quadratic variation equation for the relatonship? the variable y varies directly with x^2 and y=36 when x=

3
Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

For this case we have a direct variation of the form:

y = kx ^ 2

Where,

  • <em>k: proportionality constant </em>

We must find the value of k.

For this, we use the following data:

y = 36\\x = 3

Therefore, replacing values we have:

36 = k (3) ^ 2

Rewriting:

36 = 9k

Clearing the value of k we have:

k = \frac {36} {9}\\k = 4

Therefore, the direct variation equation is given by:

y = 4x ^ 2

Answer:

The quadratic variation equation for the relatonship is:

y = 4x ^ 2

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Solve for x: <br><br> 9x - 3 = -39<br><br><br> a -6<br><br> b -4<br><br> c 9<br><br> d 5
ahrayia [7]
<span>9x - 3 = -39
9x = -39 + 3
9x = -36
x = -36/9
x = -4

</span><span>Answer: b -4</span>
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Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle, or a parallelogram. The
vodomira [7]

Answer:

2) ABCD is  a RECTANGLE.

Perimeter  =  30 units

Step-by-step explanation:

Here, the given points of the quadrilateral are:

A(6, –4), B(11, –4), C(11, 6), D(6, 6)

Now, if P(a,b) and Q(c,d) are any two given points, then the distance between them is given by DISTANCE FORMULA as:

PQ = \sqrt{(c-a)^2 + (d-b)^2

Use this to find the length of all 4 sides:

AB with coordinates A(6, –4), B(11, –4)  is given as:

AB = \sqrt{(11-6)^2 + (-4-(-4))^2} =  \sqrt{(5)^2 + 0} = 5

⇒ AB = 5 units

BC with coordinates B(11, –4), C(11, 6)  is given as:

BC = \sqrt{(11-11)^2 + (6-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

⇒ BC = 10 units

CD with coordinates C(11, 6), D(6, 6)  is given as:

CD = \sqrt{(11-6)^2 + (6-6)^2} =  \sqrt{(5)^2 + 0} = 5

⇒ CD = 5 units

AD with coordinates A(6, –4),D(6, 6)  is given as:

AD = \sqrt{(6-6)^2 + (-4-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

⇒ AD = 10 units

Now, here AB  = CD =  5 units, AD = BC  = 10 units

Also, in a RECTANGLE, OPPOSITE SIDES ARE EQUAL IN LENGTH.

Hence, ABCD is  a RECTANGLE.

Perimeter  = AB + BC+ CD  + AD = 5 + 10 + 5 + 10 = 30 units

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Please help me !!! and explain your answer !!!<br> solve for L :
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L = \frac{P}{2} - W

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divide both sides by 2

\frac{P}{2} = L + W

subtract W from both sides

\frac{P}{2} - W = L


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