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3 years ago

Can someone answer number 5 plz

Mathematics

1 answer:

Georgia [21]3 years ago

5 0

Answer:

C) 113 m^2

Step-by-step explanation:

diameter/2 =radius = 12/2 = 6

area = 6^2(3.14) = 6x6x3.14 = 113 m^2

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Write an equation to describe the relationship between the independent variable x and the dependent variable y.

AlexFokin [52]

Answer:

x=y+2

Step-by-step explanation:

4 0

3 years ago

A 6 inch personal pizza has 640 calories, with 240 of those from fat. A 12 inch pizza is cutinto 8 slices. Estimate the number o

MissTica

Given:

Number calories in a 6-inch pizza = 640 calories

For the pizza of 6 inch

$A=\pi(3)^2=9\pi$

For the pizza of 12 inch

$A=\pi(6)^2=36\pi$

Number calories in a 6-inch pizza = 640 calories, therefore:

$\frac{A_{6\text{ inch}}}{A_{12\text{ inch}}}=\frac{640}{x}$

Substitute:

$\begin{gathered} \frac{9\pi}{36\pi}=\frac{640}{x} \\ Simplify \\ \frac{1}{4}=\frac{640}{x} \end{gathered}$

And solve for x:

$\begin{gathered} 1\cdot x=4\cdot640 \\ x=2560 \end{gathered}$

Now, Estimate the number of calories in one slice of a 12 inch pizza:

$\frac{2560}{8}=320$

Answer: 320 calories

4 0

1 year ago

the ages of three siblings are all consecutive integers the sum of their ages is 39 how old is the youngest sibling variable equ

Verdich [7]

Answer:

Step-by-step explanation:

Let x = the age of the youngest child

Let x + 1 = the age of the middle child

Let x + 2 = the age of the oldest child

x + x + 1 + x + 2 = 39

3x + 3 = 39

3x = 36

x = 12 years

8 0

2 years ago

What is 3h^2+6h-18x as a product of two factors?? Please help,*a lot of points*

Vaselesa [24]

-3 is one of them hope this helps

4 0

3 years ago

(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard

AveGali [126]

Answer:

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.95=0.05$

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: $t_{n-1,\alpha/2}=t_{7,0.025}=2.365$

Sample mean : $\overline{x}=24.8\text{ hours}$

Standard deviation : $\sigma=3.2\text{ hours}$

The confidence interval for population means is given by :-

$\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}$

$24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)$

Hence, the 95% confidence interval, assuming the times are normally distributed.= (22.12, 27.48)

6 0

3 years ago