Answer: the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Explanation:
We know that; Gram negative bacteria looks pale reddish in color under a light microscope from Gram staining.
therefore
There are 30 red bacterial colonies counted.
1 mL of from tube 1 was removed and added to tube with 99 mL saline (tube 2) dilution is 1/100.
transferred volume into the plate is 1 mL.
Now, we have to determine the cfu/g Gram-negative bacteria in the fecal sample
Formula to calculate CFU/g bacteria in fecal sample is expressed as;
C = n/(s×d )
where C is concentration (CFU/g)
, n is number of colonies
, s is volume transferred to plate
, d is dilution factor.
so we substitute
C = 30 / ((1/100) × 1)
C = 30 / 0.01
C = 3000
C = 3.0 × 10^3
THERFERE, the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Answer:
answer should be "making water hypoxic for organisms". reason is because the runoff from these treatment plants are filled with nutrients, which will cause eutrophication. eutrophication is excessive algae sprouts which create more DO but then later becomes all used up when they decompose, making it so other organisms have no oxygen.
The main component in three investigations is that in my opinion The common denominator of the fact that they are all three still investigations.
Answer:
Part 1:
Correct option is A: "NaDP+/NaDPH"
Part 2:
Correct option is F: "glucose 6-phosphate dehydrogenase"
Explanation:
Various levels of control are put in place to keep a check on the pathway. This is an example of one such control. This dehydrogenase enzyme is responsible to control the rate of reaction and it is stimulated by NADP+ while it is inhibited by NaDPH. The oxidative reaction is under the influence of the NaDP+/NaDPH concentration, which is catalyzed by glucose 6-phosphate dehydrogenase.
Hope that answers the question, have a great day!
Answer:
this is a transform plate boundary (AKA- transform fault)
hope this helps :)
