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NikAS [45]
3 years ago
12

 if xy=c^2, prove that x^2 dx/dy+c^2=0

Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0
Hello,

xy=c²==>y=c²/x
==>y'=dy/dx=-c²/x²==>x² dy/dx+c²=0 (there is a mistake)

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Answer:

\boxed{  \text{Option \: D}}

Step-by-step explanation:

All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called vertical line test.

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--------------------------------------------------

Let's check all of the options :

☐ Option A :

  • The vertical line cuts the graph at two points. So , the graph does not represent a function.

☐ Option B

  • No! This is also not a function as the vertical line cuts the graph at two points.

☐ Option C

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☑ Option D

  • Yep! The vertical line cuts the graph at one point. Thus , the graph represents a function.

Yayy!! We found our answer. It's ' Option D '.

Hope I helped ! ツ

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Step-by-step explanation:

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