if xy=c^2, prove that x^2 dx/dy+c^2=0
1 answer:
You might be interested in
The geometrical relationships between the straight lines AB and CD is that they are parallel to each other
<h3>How to determine the relationship</h3>It is important to note the following;
- A drawn from the origin and passes through point A (a , b), then the equation of OA = ax + by
- If a line is drawn from the origin and passes through point B (c , d), then the equation of OB = cx + dy
We find the equation of AB by subtracting OB from OA, thus AB = (c - a)x + (d - b)y
The slope of line AB =
⇒ OA= 2 x + 9 y
⇒ OA = 4 x + 8 y
⇒AB = OB - OA
⇒AB = (4 x + 8 y) - (2 x + 9 y)
⇒ AB = 4 x + 8 y - 2 x - 9 y
Collect like terms
⇒ AB = (4 x - 2 x) + (8 y - 9 y)
⇒AB = 2 x + -y
⇒ AB = 2 x - y
⇒ Coefficient of x = 2
⇒ Coefficient of y = -1
⇒ The slope of ab = = 2
For CD
⇒ CD = 4 x - 2 y
⇒Coefficient of x = -4
⇒ Coefficient of y = -2
⇒The slope of cd = = 2
Note that Parallel lines have same slopes
And Slope of ab = slope of cd
AB // CD
Therefore, the geometrical relationships between the straight lines AB and CD is that they are parallel to each other
Learn more about parallel lines here:
#SPJ1