Ask question

Ask question

All categories

3 years ago

11

Please please help me and fast

1 answer:

Eduardwww [97]3 years ago

4 0

Its 12. Part a was 2 part b was 3
6×2=12
4×3=12

You might be interested in

Please help i put a picture on top

jolli1 [7]

Answer:

1/8÷7

Step-by-step explanation:

I think

3 0

3 years ago

The area of a rectangular dining room is 16 square meters. The perimeter is 16 meters. What are the dimensions of the dining roo

neonofarm [45]

Answer:

4

Step-by-step explanation:

The area is 16, and you know that it's 2 sides u need to multiply

The perimeter is 16, and you know that you need to add up all the sides

So....

A = b * h

A = 4 * 4

A = 16 CORRECT

And....

P = S + S + S + S ( s = sides)

P = 4 + 4 + 4 + 4

P = 16 CORRECT

Hope this helped!

Have a supercalifragilisticexpialidocious day!

6 0

3 years ago

Find the area of the figure below<br><br> A.832in^2<br> B.768^2<br> C.416^2<br> D.384in^2

lesantik [10]

The area is the average of the 2 heights times the base, which is:
(24+16)/2*19.2=384 in^2=D

6 0

3 years ago

find the point on the terminal side of θ = negative three pi divided by four that has an x coordinate of negative 1

Mila [183]

Check the picture below, is a negative angle, thus, is going "clockwise"

$\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad tan\left( -\frac{3\pi }{4} \right)=\cfrac{y}{x}\implies tan\left( -\frac{3\pi }{4} \right)=\cfrac{y}{-1}
\\\\\\
-1\cdot tan\left( -\frac{3\pi }{4} \right)=y\implies -1\cdot \cfrac{sin\left( -\frac{3\pi }{4} \right)}{cos\left( -\frac{3\pi }{4} \right)}=y
\\\\\\
-1\cdot \cfrac{-1}{-1}=y\implies -1$

4 0

3 years ago

A resident of Bayport claims to the City Council that the proportion of Westside residents

Kazeer [188]

Answer:

The test statistics is $z = -1.56$

The p-value is $p-value = 0.05938$

Step-by-step explanation:

From the question we are told

The West side sample size is $n_1 = 578$

The number of residents on the West side with income below poverty level is $k = 76$

The East side sample size $n_2=688$

The number of residents on the East side with income below poverty level is $u = 112$

The null hypothesis is $H_o : p_1 = p_2$

The alternative hypothesis is $H_a : p_1 < p_2$

Generally the sample proportion of West side is

$\^{p} _1 = \frac{k}{n_1}$

=> $\^{p} _1 = \frac{76}{578}$

=> $\^{p} _1 = 0.1315$

Generally the sample proportion of West side is

$\^{p} _2 = \frac{u}{n_2}$

=> $\^{p} _2 = \frac{112}{688}$

=> $\^{p} _2 = 0.1628$

Generally the pooled sample proportion is mathematically represented as

$p = \frac{k + u}{ n_1 + n_2 }$

=> $p = \frac{76 + 112}{ 578 + 688 }$

=> $p =0.1485$

Generally the test statistics is mathematically represented as

$z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2} ]} }$

=> $z = \frac{ 0.1315 - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688} ]} }$

=> $z = -1.56$

Generally the p-value is mathematically represented as

$p-value = P(z < -1.56 )$

From z-table

$P(z < -1.56 ) = 0.05938$

So

$p-value = 0.05938$

3 0

3 years ago