Answer:
y = 14
Step-by-step explanation:
Since AC = BC then the triangle is isosceles and the base angles are congruent, that is
∠A = ∠B = 50°, thus
∠C = 180 - (50 + 50) ← sum of angles in Δ = 180°
= 180 - 100 = 80°, hence
5y + 10 = 80 ( subtract 10 from both sides )
5y = 70 ( divide both sides by 5 )
y = 14
Answer:
- 3
Step-by-step explanation:

Price per box, P = $1.45 .
Money left, M = $1247 - $472.70 = $774.3 .
Let, number of boxes are x.
So,

Therefore, they have to sell 534 more boxes.
Hence, this is the required solution.
Answer:
a. 19.68 miles per gallon.
b. 26.32 miles per gallon.
Step-by-step explanation:
Mean gas mileage (μ) = 23.0 mpg
Standard deviation (σ) = 4.9 mpg
In a normal distribution, for any length X, the z-score is determined by the following expression:

In a normal distribution, the 25th percentile (first quartile) of a normal distribution has a corresponding z-score of z = -0.677 and the 75th percentile has a corresponding z-score of z = 0.677
a. The first quartile of the distribution of gas mileage is

19.68 miles per gallon.
b. The third quartile of the distribution of gas mileage is

26.32 miles per gallon.
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27