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Paul [167]
3 years ago
14

How do you do algebra?

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0

Answer:

Lol its a bunch of formula's but once you get those down it shouldn't be as hard. And the order of operations, some people forget how to subtract in middle school believe it or not.

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Kailey buys a greeting card for $3.79. She then buys 3 postcards that all cost the same amount. The total cost is $6.04. How muc
leonid [27]

Answer:

0.75 was how much she paid for each postcard.

Step-by-step explanation:

6.04-3.79

=2.25

so take 2.25 divided by 3

= o.75

equations would be 6.04-3.75=b/ 3

5 0
3 years ago
10 raised to negative 3 in standard notation
larisa86 [58]
Standard notation simply means the normal way or writing numbers.
10^-3= 1/10^3
1/10^3=1/1000
1/1000=0.001
Final answer: 0.001
4 0
3 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
A solid object where the radius of bse is 7cm and height is 12cm​
Andreyy89

Answer:

A cylinder with a base radius of 7cm and a height of 12 cm.

5 0
3 years ago
Read 2 more answers
If A = -3n + 2, and B = 5n - 7, what is the value of A + B, in simplest form?
Sever21 [200]

Answer:

I think the answer is 2n-5

(-3n + 2)+(5n - 7)

-3n+5n=2n

2+(-7)=-5

4 0
3 years ago
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