<span>7 no encaja en 4, por lo que la respuesta sería cero 7 ajustes en 4, cero veces</span>
Answer:
please give me a brainless 0
Inequality :
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
The following is as far as I get:
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1
n−1−(⌊n÷m⌋×(a−b))≥x−α1a
n−(⌊n÷m⌋×(a−b))≥x−α1a + 1
Step-by-step explanation:
Answer:

Step-by-step explanation:
we are given a quadratic function

we want to figure out the minimum value of the function
to do so we need to figure out the minimum value of x in the case we can consider the following formula:

the given function is in the standard form i.e

so we acquire:
thus substitute:

simplify multiplication:

simply division:

plug in the value of minimum x to the given function:

simplify square:

simplify multiplication:

simplify:

hence,
the minimum value of the function is -155
Answer:
That something unexpected is about to happen.
Step-by-step explanation:
The 3 numbers which should be placed between 12 and 60 are; 24, 36 and 48.
<h3>What three numbers should be placed between 12 and 60?</h3>
It follows from the task content that the first and last numbers are; 12 and 60 respectively.
Hence, since the difference between 12 and 60 is 48 and there are 4 transitions between the two numbers to have 5 total numbers,
It follows that the common difference is; 48/4 = 12 and the three numbers required are; 24,36 and 48.
Read more on common difference;
brainly.com/question/19601308
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