<h3>Charlene left city A at 10: 10 AM</h3>
<em><u>Solution:</u></em>
Given that,
At 10 a.m., Hillary left City A and drove at an average speed of 120 km/h
Charlene drove at an average speed of 144 km/h and took 50 minutes.
She arrived at City B at the same time as Hillary
Their distance is same
Find the ratio of speed
120 : 144
Reduce to lowest term
Hillary : charlne = 5 : 6
Find the ratio of time:
Since, speed and time are inversely propotional
Hillary : charlne = 6 : 5
Let time taken by Hiliary be 6t
Let time taken by charlene be 5t
Given that, Charlene took 50 minutes
Therefore,
5t = 50
t = 10
Thus,
time taken by Hiliary = 6t = 6(10) = 60
Thus hiliary took 60 minutes to reach
<em><u>Find the time Charlene left City A</u></em>
At 10 a.m., Hillary left City A
Difference between both their time = 60 - 50 = 10 minutes
Thus, Hilairy left city A = 10 am + 10 minutes = 10 : 10 a.m
Thus, Hillary left city A at 10: 10 AM
