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guajiro [1.7K]
3 years ago
12

Tom started an entertainment company. The net value of the company (in thousands of dollars) ttt months after its creation is mo

deled by v(t)=4t^2-24t-28v(t)=4t 2 −24t−28v, left parenthesis, t, right parenthesis, equals, 4, t, squared, minus, 24, t, minus, 28 Tom wants to know when his company will be at its lowest net value. 1) Rewrite the function in a different form (factored or vertex) where the answer appears as a number in the equation. v(t)=v(t)=v, left parenthesis, t, right parenthesis, equals 2) How many months after its creation does the company reach its lowest net value? months
Mathematics
1 answer:
Furkat [3]3 years ago
8 0

Step-by-step explanation:

Given the expression for the net value of an entertainment company after t months modeled by the equation;

v(t)=4t²-24t-28

1) To write the expression in a factored form, we need to factorize the equation given;

v(t)=4t²-24t-28

divide through by 4

v(t)=t²-6t-7

v(t)= t²-7t+t-7

v(t)= t(t-7)+1(t-7)

v(t)= (t+1)(t-7)

Hence the function in a factored or vertex form is v(t)= (t+1)(t-7)

2) To know the number of months after the company creation that the company reaches its lowest value, we will substitute v(t) = 0 into the factored form of the expression as shown;

v(t)= (t+1)(t-7)

0 = (t+1)(t-7)

(t+1)(t-7) = 0

t+1 = 0 and t-7 = 0

t = -1 and t = 7

But t cannot be negative

Hence t = 7 months

This means that the company reaches its lowest net value after 7 months

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Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

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Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312

Probability of having an emergency locator and not being discovered:

20% of 28%. So

P(A cap B) = 0.2*0.28 = 0.056

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

P(A) = 1 - 0.5312 = 0.4688

Probability of not having an emergency locator and being discovered:

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Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

P(A \cap B) = 0.66*0.72 = 0.4752

Probability of being discovered, given that it has the emergency recorder:

p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946

This question asks for P(X = 7) when n = 10. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064

0.064 = 6.4% probability that 7 of them are discovered.

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