Hi!
An obtuse angle is one greater than 90 degrees, a right angle one that is 90, and acute less than 90.
An obtuse triangle is one with one obtuse angle, all the rest being acute. A right triangle is one with one right angle, all the rest acute. And finally, an acute triangle is one with three acute angles.
In this case, the angles measure 83 degrees, 31 degrees, and 66 degrees. All of them are acute angles, as they're all less than 90 degrees.
Therefore, the triangle is an acute triangle.
Hope this helped!
Answer:
Country A = 84
Country B = 28
Country C = 18
Step-by-step explanation:
Country A, Country B, and Country C won a total of 130 medals;
A + B + C = 130 ......1
Country B won 10 more medals than Country C;
B = C + 10 .......2
Country A won 38 more medals than the total amount won by the other two;
A = B + C + 38 ........3
Substituting equation 3 to 1;
(B+C+38) + B+C = 130
2B + 2C + 38 = 130 .......4
Substituting equation 2 into 4;
2(C+10) + 2C + 38 = 130
4C + 58 = 130
4C = 130-58 = 72
C = 72/4 = 18
B = C + 10 = 18 + 10 = 28
A = B + C + 38 = 18 + 28 + 38 = 84
Country A = 84
Country B = 28
Country C = 18
Answer:
x=-2
Step-by-step explanation:
Given points are (-2,2) and (-2,-3).
Now we need to find equation of the line passing through the given points.
So let's begin by finding slope
which is undefined. That means graph of the line must be vertical as you can see that in given points, x-value is not changing.
Equation of vertical line is given by x=k where k is the fixed value of x-coordinate.
x-coordinate is -2 in given points.
Hence final equation is x=-2.
Can't reallly see the paper
Answer:
0.82
Step-by-step explanation:
The question says that three percent (3 out of 100) of the rackets (racquets) produced by the company are found to be defective.
First thing to calculate is the probability that 1 in a box of 6 rackets are defective.
That probability is gotten by cross multiplying, as illustrated below;
3 - 100
x - 6
x = (6×3)/100 = 18/100 = 0.18
Since the probability of having/finding 1 defective racket in a box of 6 is 0.18, the probability of finding more than 1 (minimum of 2 and maximum of all six) defective rackets in same box would be (1 - 0.18) = 0.82
