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kirill [66]
3 years ago
12

A company producing tennis racquets found that 3% of the racquets they produce are defective. The racquets are sent to shops in

boxes of 6 and the shops send back boxes with more than one defective racquet. If a box is chosen at random and opened, what is the probability that it is sent back
Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

0.82

Step-by-step explanation:

The question says that three percent (3 out of 100) of the rackets (racquets) produced by the company are found to be defective.

First thing to calculate is the probability that 1 in a box of 6 rackets are defective.

That probability is gotten by cross multiplying, as illustrated below;

3 - 100

x - 6

x = (6×3)/100 = 18/100 = 0.18

Since the probability of having/finding 1 defective racket in a box of 6 is 0.18, the probability of finding more than 1 (minimum of 2 and maximum of all six) defective rackets in same box would be (1 - 0.18) = 0.82

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Answer:

24 divided by 3/4 =32

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Step-by-step explanation:


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A cheetah ran 275 feet in 3.23 seconds. How fast did the cheetah run in miles per hour? Round your answer to the nearest whole m
yawa3891 [41]
First we convert feet into meters, since 1 feet is 0.3048 m: 275 feet * 0.3048 = 83.82m.

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8 0
3 years ago
Brainliest
crimeas [40]

Answer:

2) age increases and the height increases with it

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4 0
3 years ago
The speeds of cars on a given i street we are normally distributed with a mean of 72 miles per hour and a standard deviation of
Ostrovityanka [42]

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Step-by-step explanation:

Let X be a random variable that represents the speed of the drivers.

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The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:

P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278

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