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andrezito [222]
3 years ago
15

What is the solution of the equation 4[x + 2(3x – 7)] = 22x – 65?

Mathematics
2 answers:
Anni [7]3 years ago
5 0
4 (X + 2 (3X - 7)) = 22X - 65
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation:
4 * (X + 2 * (3 * X - 7)) - (22 * X - 65) = 0
Pull out like factors:
7X - 14 = 7 * (X - 2)
28 * (X - 2) - (22X - 65) = 0
Pull out like factors:
6X + 9 = 3 * (2X + 3)
3 * (2X + 3) = 0
3 = 0... (equation never true, has no solution; a a non-zero constant never equals zero)
2X + 3 = 0
Subtract (-3) from both sides of the equation:
2X + 3 (-3) = 0 + (-3)
2X + 3 - 3 = 0 - 3
2X + 0 = -3
2X = -3

Divide both sides of the equation by 2:
2x / 2 = -3 / 2
X = -3 / 2
X = - 1.500

Lelu [443]3 years ago
3 0
X = -3/2
I hope my work .... helped you out a little.

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Answer:

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Step-by-step explanation:

System of equations (q = # of quarters, n = # of nickels):

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the first equation can be changed to q = 70 - n, so we are able to <em>substitute q with 70 - n</em>.

So, it will look like <em>0.25*70 - 0.25n + 0.05n = 7.50</em>. This can be simplified to <em>0.2n = 10</em>, which means that n = 50.

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hope its help full thank u❤️❤️❤️

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