Answer:
-63 / 7
Step-by-step explanation:
Answer:
5740
Step-by-step explanation:
Answer:
Problem 7) C
Problem 8) B
Step-by-step explanation:
Recall that inverse variation has the form:

Where <em>k</em> is the constant of variation.
Problem 7)
We are given that <em>y</em> = 39 when <em>x</em> = 1/3. Thus:

Solve for <em>k: </em>
<em />
<em />
<em />
Hence, our equation is:

Then when <em>x</em> = 26, <em>y</em> equals:

Problem 8)
We are given that <em>y</em> = 25 when <em>x</em> = -1/5. Thus:

Solve for <em>k: </em>
<em />
<em />
<em />
Hence, our equation is:

Answer:x=3
Step-by-step explanation:
D( x )
x+2 = 0
x = 0
x+2 = 0
x+2 = 0
x+2 = 0 // - 2
x = -2
x = 0
x = 0
x in (-oo:-2) U (-2:0) U (0:+oo)
(9*x-7)/(x+2)+15/x = 9 // - 9
(9*x-7)/(x+2)+15/x-9 = 0
(x*(9*x-7))/(x*(x+2))+(15*(x+2))/(x*(x+2))+(-9*x*(x+2))/(x*(x+2)) = 0
x*(9*x-7)+15*(x+2)-9*x*(x+2) = 0
9*x^2-9*x^2+8*x-18*x+30 = 0
30-10*x = 0
(30-10*x)/(x*(x+2)) = 0
(30-10*x)/(x*(x+2)) = 0 // * x*(x+2)
30-10*x = 0
30-10*x = 0 // - 30
-10*x = -30 // : -10
x = -30/(-10)
x = 3
x = 3