Answer:
![\sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Step-by-step explanation:
At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:
![\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%5Csqrt%20%5B4%5D%20%7Bx%5E2%7D%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20%5Csqrt%5B4%5D%7Bx%5E2%5Ccdot%20x%7D%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Alternatively, if you're allowed to use rational exponents, we can convert everything:
![\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}](https://tex.z-dn.net/?f=%5Csqrt%20x%20%5Ccdot%20%5Csqrt%5B4%5D%20x%20%3D%20x%5E%7B%5Cfrac12%7D%20%5Ccdot%20x%5E%5Cfrac14%20%3D%20x%5E%7B%5Cfrac12%20%2B%5Cfrac14%7D%3D%20x%5E%7B%5Cfrac24%20%2B%5Cfrac14%7D%3D%20x%5E%5Cfrac34%20%3D%20%5Csqrt%5B4%5D%20%7Bx%5E3%7D)
Answer:
D I and IV
Step-by-step explanation:
The opposite of an integer "x" is "-x".
I. The integer is 53. → Since the opposite of George's integer is -53, the integer is -(-53) = 53
II. The integer has an absolute value of - 53. → The absolute value of 53 is 53.
III. The integer is - 53. → It was 53, found in I.
IV. The integer has an absolute value of 53. → It has an absolute value of 53, found in II.
Answer:
5.24, 21/4, or 5 and 1/4
Step-by-step explanation:
78+139+14 = 231
231/44 = 5.25
Or 21/4 (improper fraction)
Or 5 and 1/4 (mixed number)
I'm not exactly sure what you were asking I hope that helps!
Answer:
See explanation
Step-by-step explanation:
Start by dividing the isosceles triangle in half along the upper vertex angle (not the congruent base angles). This creates two right triangles. Since you divide the triangle in half along an angle, they both have an equal base angle, and they share a side, they are congruent by ASA. Since the corresponding sides of congruent triangles are equal, the sides opposite the congruent base angles of a triangle must be congruent.
Hope this helps!
