Find the distance (-4, 6) and (3 - 7)
2 answers:
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The perimeter of ΔXYZ is 126 units.
Solution:
Given ΔPQR ΔXYZ.
In ΔPQR,
PQ = 5, QR = 10, PR = 6
In ΔXYZ, XY = 30
Perimeter of ΔPQR = PQ + QR + PR
= 5 + 10 + 6
= 21
Perimeter of ΔPQR = 21
To find the perimeter of ΔZYZ:
If two triangles are similar then the ratio of the perimeters of two similar triangles is same as the ratio of their corresponding sides.
Do cross multiplication, we get
⇒ 5 × Perimeter of ΔXYZ = 30 × 21
⇒ 5 × Perimeter of ΔXYZ = 630
Divide by 5 on both sides of the equation.
⇒ Perimeter of ΔXYZ = 126
Hence the perimeter of ΔXYZ is 126 units.