1) f(x)=2x+6
f(2)=2(2)+6
=4+6
=10
2)f(x)=3x
f(a+1)=3(a+1)
=3a+3
3)f(x)=3x-1 and g(x)=5x+3
f(2)=3(2)-1
f(2)=6-1
=5
g(3)=5x+3
=5(3)+32
=15+3
=18
f(2)+f(3)=5+18
=23.
I hope this helps you
perpendicular lines slopes multiplication -1
M1×M2= -1
1/2×M2= -1
M2= -2
Answer:
3.
7.608
Step-by-step explanation:
An irrational number is any number which can't be written as a fraction this way. For example, pi and the square root of two cannot be expressed as a fraction of two whole numbers, so they are both irrational.
if we make the respective accounts in the first and second problem we will see that they are irrational numbers
the fourth is a periodic number, which falls within the irrational
the only rational is the third
I'm assuming that you meant 4x+1=3x?
Subtracting 4x, we get 1=-x. Multiplying by -1, we get x=-1 as the solution.
