Question

On a coordinate plane, square P Q R S is shown. Point P is at (4, 2), point Q is at (8, 5), point R is at (5, 9), and point S is at (1, 6). Which statement proves that the diagonals of square PQRS are perpendicular bisectors of each other? The length of SP, PQ, RQ, and SR are each 5. The slope of SP and RQ is Negative four-thirds and the slope of SR and PQ is Three-fourths. The length of SQ and RP are both StartRoot 50 EndRoot. The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.

Answer 1

Answer:

(D)The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.

Step-by-step explanation:

• Point P is at (4, 2),
• Point Q is at (8, 5),
• Point R is at (5, 9), and
• Point S is at (1, 6)

Midpoint of SQ $=\frac{1}{2}(1+8,5+6)=(4.5,5.5)$

Midpoint of PR $=\frac{1}{2}(4+5,2+9)=(4.5,5.5)$

Now, we have established that the midpoints (point of bisection) are at the same point.

Two lines are perpendicular if the slope of one is the negative reciprocal of the other.

In option D

• Slope of RP =7

• Slope of SQ  $=-\dfrac17$

Therefore, lines RP and SQ are perpendicular.

Option D is the correct option.