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zaharov [31]
3 years ago
13

'X' years ago, Rakesh's age was twice his brother's age and '4X' years ago, Rakesh's age was thrice his brother's age. If it is

known that 'X' is a natural number, then what can be the absolute difference between their present ages? plz answer it fast it's urgent​
Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer: The difference must be a multiple of 6

Step-by-step explanation:

R is Rakesh's age and B is the age of the brother.

the equations we have are:

(R - X) = 2*(B - X)

(R - 4X) = 3*(B - 4X)

where X must be a natural number.

we can write it as

(R - B) = -X + B

(R - B) = 2B - 8X

-X + B = 2B - 8X

B = 7X

then:

R - 7X = 6X

This means that the difference between their ages is a multiple of 6, for example, if the difference between them is 12 years, we have X = 2

R - 2 = 2*B - 4

R - 8 = 3*B - 24

in the first equation:

R = 2*B - 2

we replace it in the second eq:

2*B - 10 = 3*B - 24

B = 14 = 7*X = 7*2

and R = 14 + 12 = 26

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