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Ede4ka [16]
3 years ago
7

3 l = _____ dl A. 0.3 B. 0.03 C. 300 D. 30

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer: The correct option is D, i.e.,30.

Explanation:

It the given equation we have two units l and dl.

Where l represents the liter and dl represents the deciliter. These are the volume units.

We know that,

1 liter = 10 deciliter

It means,

1 l = 10 dl

Multiply both sides by 3,

1\times 3 l = 10\times 3 dl

3 l = 30 dl

Therefore, the correct option is D and 3 l = 30 dl.

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The volume of a cylinder is 252π cm3 and its height is 7 cm. What is the cylinder’s radius? A. 36 B. 80 C.16 D.6
REY [17]
Put the given information into the formula and solve for the variable of interest.
.. V = π*r^2*h
.. 252π = π*r^2*7
.. (252π)/(7π) = r^2
.. 36 = r^2
.. 6 = r

The radius is 6 cm. Selection D is appropriate.

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We would prefer that the offered selections had the appropriate cm units attached.
5 0
3 years ago
Find the slope of the line on the graph
yulyashka [42]
Y=mx+b 
b= -2 
m= rise/run = 2/3 
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7 0
3 years ago
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
ASAP HELP PLEASE! WILL GIVE BRAINLIEST
Mila [183]

Answer:

  1. Least Value = 2
  2. Median = 6
  3. Greatest Value = 10
  4. Third Quartile = 8
  5. Range = 8 (10 - 2 = 8)
  6. First Quartile = 5

Step-by-step explanation:

7 0
3 years ago
If the product of two rational numbers is (-9/16) and one of them is (-4/15) find the other number.​
ololo11 [35]

Given:

  • The product of two numbers is (-9/16).
  • One of the numbers is (-4/15)

To find: The other number.

Answer:

Let's assume the unknown number to be 'x'.

(-4/15) × x = (-9/16)

× = (-9/16) ÷ (-4/15)

When we divide a fraction by another fraction, the divisor will be taken in its reciprocal form.

x = (-9/16) × (-15/4)

x = 135/64

Therefore, the other number is 135/64.

Hope it helps. :)

8 0
3 years ago
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