Ask question

Ask question

All categories

3 years ago

6

Select the equation that contains the points, (-6,5/2) and (4, 10)?

1 answer:

alexandr1967 [171]3 years ago

4 0

Let y=Mx+B be the equation of our line running the through points (-6,5/2) and (4,10). Our slope M = (y2-y1) ÷ (x2-x1) = (10-5/2) ÷ [4-(-6)] = (15/2) ÷ 10 = ¾. Picking (4,10) as our point solve for b:
y = Mx + B
10=¾*4 + B = 3 + B.
So B = 7. Therefore our equation of our line is given by y=¾x + 7.

You might be interested in

Please help find the value of x<br> find value angle of WAY <br> find value angle of XAY

stealth61 [152]

Answer:

(x-10)° + (x + 14)° = 180°

=> x° - 10° + x° + 14 ° = 180°

=> 2x° + 4° = 180°

=> 2x° = 176°

=> x° = 176°/ 2

=> x° = 88°

Therefore the magnitude of x° = 88° (ans)

5 0

3 years ago

What is the absolute value of 6.75?

dusya [7]

6.75 is the absolute value of 6.75 absolute value is distance from zero and 6.75 is 6.75 from 0 so is -6.75

6 0

4 years ago

Read 2 more answers

-x+7-6x=19-7x<br>Determine whether this has one solution, no solution, or infinitely many solutions

rewona [7]

Reduces to ,7=19. no solutions

6 0

4 years ago

Helpp meee please!!!! asap

Vladimir [108]

A. x-6=6

if u plug in 12, you get 12-6=6 which is true
all the other ones would be false if you plugged in 12

3 0

3 years ago

Five the equation of line that is perpendicular to f(x)=-2x+1 that goes through point (0,5)

Alinara [238K]

Answer:

y = $\frac{1}{2}$ x + 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

f(x) = - 2x + 1 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$ , then

y = $\frac{1}{2}$ x + c

the line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = $\frac{1}{2}$ x + 5 ← equation of perpendicular line

7 0

2 years ago