Not the way you wrote it, it isn't. Nothing you wrote is repeated, and
there's no note saying that the 561, or the 61, or the 1 repeats.
In order to solve a triangle, you need three of the six bits of information that define the triangle (3 angles, 3 sides), including at least one side. If you have one angle and one side, you only have two, not three. The triangle cannot be solved.
However, if your triangle is a right triangle, and the angle referred to in the problem statement is not the right angle, then you have the required information. In general, you make use of the definitions of the trigonometric functions. These can be remembered by the mnemonic SOH CAH TOA.
ok if GH line length is that 8.6 you do the following:
since OH and OG are radiuses they are equal, we have in the triangle two equal angles beside 82 means each angle is 49 degree, now use "sine law" sine 82 / GH (8.6) = sine 49 / OH, OH equal 6.55, this is the radius, theta = arc/radius, provided that theta is in radian, 82 degree in radians would be 1.43 something multiply that by 6.55 (radius) you get arc GH = 9.4, since GH and HJ arcs are congruent hj = 9.4, if the answer is wrong tell me to revise in case you have a guide answre
To determine the average water use, 109 people must be sampled.
1.9 gallons is the standard deviation.
E = 0.15 gallons maximum error
1.9 gallons on average
90% is the critical value.
1.645 is the 90% confidence interval.
sample size requirement,
n = (((z ÷ 2) × σ) ÷ E)²
n = (((1.645 ÷ 2) × 1.9) ÷ 0.15)²
n = ((0.8225 × 1.9) ÷ 0.15)²
n = (1.5627 ÷ 0.15)²
n = (10.418)²
n = 108.53 ≈ 109
As a result, the minimal sample size necessary to determine the mean water use = 109.
It is determined by dividing the average standard error by the squared of the sample size, and it decreases with increasing sample size. In other words, when the sample size is sufficiently big, the population mean approaches the population mean.
To learn more about the sample interval at
brainly.com/question/13664567?referrer=searchResults
#SPJ4
Answer:
47.33
Step-by-step explanation:
I solved it on paper
