Answer:
Step-by-step explanation:
Given Ben's observations when the wait time is as advertised represented by the equation 2|x − 2| − 12 = 0, to get the times when the serving time is as advertised, relative to noon, we will calculate for the value of x in the equation;
Note that the modulus of the function |x-2| will return both positive and negative value.
For the positive value of |x-2|;
2|x − 2| − 12 = 0
2(x − 2) − 12 = 0
open the parenthesis
2x-4 - 12 = 0
2x - 16 = 0
add 16 to both sides
2x-16+16 = 0+16
2x = 16
x = 16/2
x = 8
For the negative value of |x-2|;
2|x − 2| − 12 = 0
-2(x − 2) − 12 = 0
open the parenthesis
-2x+4 - 12 = 0
-2x - 8 = 0
add 8 to both sides
-2x-8+8 = 0+8
-2x = 8
x = -8/2
x = -4
<em>Hence the times when the serving time is as advertised, relative to noon are 8minutes and 4minutes </em>
Area = l × b
Length = 5 m
Breadth = 3¼ m = 13/4 m
Area =
= 5 × 13/4
= 65/4
= 16.25 m²
Therefore, area of slater's room is 16.25 m²
Answer:
1/4 of a mile in 1/10 of an hour
you can set up a proportion
(1/4)/(1/10)=2/H
you can now simplify or cross multiply
simplifying the left side
(1/4) divided by (1/10) equals (1/4) times (10/1)
(1/4)*(10/1)=10/4=5/2
5/2=2/H
cross multiply
5H=2*2
5H=4
H=4/5 of an hour or (4/5)*60=48 minutes
another solution...
2/(1/4)=8 and 8*(1/10)=8/10=4/5 of an hour or 48 minutes again
121'
48 plus 70=118
360-118=242
242/2=121
The answer is:
v ≈ 1272.35 in^3
Sorry if this does not help.
