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katovenus [111]
3 years ago
12

A circle has a circumference of 18. It has an arc of length 6. What is the central angle of the arc, in degrees?

Mathematics
1 answer:
nadya68 [22]3 years ago
4 0
Circumference: 2πr C=18 so r= 18/2π= 9π

Arc length = rθ 6=(9π)θ θ=6/9π

Convert to degrees by multiplying by 180/π

6/9π x 180/π = 120 degrees
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2.   I think the answer is 24

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3x + 5y <= 24
3 0
3 years ago
HELP!!!!PLS!!
chubhunter [2.5K]

Answer:

12 units

Step-by-step explanation:

(-7,-6)

if you reflect it over the x-axis then the second number would be changing

-6 the opposite is 6

(-7, 6)

from -6 to 6 is 12 jumps

12 units is the distance from the original point

4 0
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Effectus [21]

Answer:

24/4/-a+12=/9d

Step-by-step explanation:

7 0
3 years ago
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GalinKa [24]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solving 6x²+9x-1=0 by completing the square root method produces an equation in the form of (x+h)²=k find H and K
marishachu [46]

The value of h is 9/12 and the value of k is 35/48

<h3>How to solve the equation?</h3>

The equation is given as:

6x^2 +9x - 1 = 0

Add 1 to both sides of the equations

6x^2 +9x - 1 + 1= 0 + 1

Evaluate the sum

6x^2 +9x =  1

Divide through the equation by 6

x^2 +9/6x =  1/6

Take the coefficient of x

k = 9/6

Divide by 2

k/2 = 9/12

Square both sides

(k/2)^2 = (9/12)^2

So, we add (9/12)^2 to both sides of the equation x^2 +9/6x =  1/6

x^2 +9/6x + (9/12)^2 =  1/6 + (9/12)^2

Next, we express the left-hand side as a perfect square

(x^2 + 9/12)^2 = 1/6 + (9/12)^2

The form of the equation is given as:

(x + h)^2 = k

So, we have:

h = 9/12

k = 1/6 + (9/12)^2

Simplify

k = 1/6 + (3/4)^2

Evaluate the exponent

k = 1/6 + 9/16

This gives

k = (8 + 27)/48

Evaluate

k = 35/48

Hence, the value of h is 9/12 and the value of k is 35/48

Read more about completing the square at:

brainly.com/question/4331586

#SPJ1

5 0
1 year ago
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