Take the derivative of x^2 to get 2x.
Take the derivative of -2xy to get -2y +-2x
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
(Everytime you take the derivative of y, you write
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
.
Take the derivative of -3y^2 to get -6y
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
.
Get the terms with
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
on one side to get:
-2x
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
- 6y
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
= 2x - 2y
Take out the common factor of
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
to get:
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
[-2x - 6y] = 2x - 2y
Divide by -2x - 6y to get:
![\frac{dy}{dx}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20)
=
<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
The answer is the first 1 !!
Here is how we see if it is true!
If Clayton drives 60 miles per hour, that means, <u>t</u>hat after one hour has passed, they should have traveled 60 miles!
If we look at the number of hours that have passed between 1:30 and 4:30, it is 3 hours.
If someone travels 60 miles every hour that has passed, and they traveled for 3 hours. To find how far they have traveled we just need to multiply 60 miles by 3 hours!
Let's solve that!
60 × 3 = 180 miles!
Clayton started driving at 1:30 pm and went 60 miles per hour.
Answer: -5v-22/15
the -5v-22 are all part of the top fraction, so the 15 is the fraction bar for the whole thing.
Answer:
A = 92y + 81
Step-by-step explanation:
Because A = number of attendees and if it adds 92 each year, you times the number of years by 92 and add 81 for the ones that were already there