Consider this system of equations.
2 answers:
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From the circle geometry theorem, a tangent to a circle makes 90° angles with the radius of the circle.
RQ is perpendicular to QP
Triangle RQP is a right-angled triangle
by Pythagoras theorem
units (rounded to one decimal place)
RQ is perpendicular to QP
Triangle RQP is a right-angled triangle
by Pythagoras theorem