Answer:
(2p+7)(3p²+4p-3)
2p(3p²+4p-3)+7(3p²+4p+3)
(6p³+8p²-6p)+ (21p²+28p+21)
6p³+29p²-6p+21
Length x width will give you area so...
72 x 46 = 3,312 yards is the area
Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find

Answer:
If asking for the distance, the answer would be C.
Answer:
6. 16 meters^2, 16 meters
7. 100 milimieters^2, 40 milimeters
9. 56 centimeters^2, 30 centimeters
10. 49 inches^2, 28 inches
11. 9 meters^2, 12 meters
12. 72 yards^2, 36 yards
Step-by-step explanation:
s is for a square
A=s^2
P=4s
l+w is for a rectangle
A=lw
P=2l+2w
6. A=4^2
A= 16 meters^2
P=4*4
P= 16 meters
7. A=10^2
A=100 milimieters^2
P=4*10
P= 40 milimeters
9. A=8*7
A= 56 centimeters^2
P=2(8)+2(7)
P=30 centimeters
10. A=7^2
A=49 inches^2
P=4*7
P=28 inches
11. A= 3^2
A=9 meters^2
P=4*3
P= 12 meters
12.
A=12*6
A=72 yards^2
P= 2(12)+2(6)
P= 36 yards
Let me know if you have any questions. Also, don't forget units!