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Rufina [12.5K]
3 years ago
6

Mathematics Areas and perimeters ​

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

54.5 Sq. cm

Step-by-step explanation:

<em>area of a right angled triangle = 1/ 2 × base × height </em>

(here, the base is 8 and height is 6)

= 1/ 2 × 6 × 8

= 4 × 6

<u>= 24 Sq. cm</u>

<em>area of a circle</em> = \pi r²

(r is the radius that is diameter/ 2, and the value of \pi is 3. 14)

  • r = 10/ 2 = 5 cm

= 3. 14.× (5)²

= 3.14 × 25

<u>= 78.5 Sq. cm</u>

area of the shaded region = area of Circle - area of triangle

= 78.5 - 24

<h3>= 54.5 Sq. cm</h3>

that is option 3

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Complete the<br> proportion<br> 3 is to 4 as 75 is to...
kolezko [41]

Answer: 100

Step-by-step explanation:

\frac{3}{4} = \frac{75}{x}

3 x 25 = 75

4 x 25 = 100

3 0
3 years ago
Please help i have no clue how to do this. any tips please and thank you :)
horsena [70]
circumference= 2(pi)r OR (pi)d
d is diameter and r is radius

if the circumference is given, then you would have to work backwards.

in this case, Circumference = 78.5 ft

the equal you would use for the radius would be 78.5 = 2 x 3.14(pi) x r
- multiply 2 x 3.14 and get 6.28
- divide 6.28 on both sides to get ‘r’ by itself
- 12.5 = r

next, for the diameter you can use C= (pi) x d
- 78.5 = 3.14 x D
- divide 3.14 on both sides to get ‘d’ by itself
- 25 = d

hope this helps! make brainliest please
3 0
3 years ago
Which of the following does not describe 10x?
never [62]
I think it would be A.
hopefully this helped ᵔᴥᵔ
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5 0
4 years ago
8 = 1 over -3 +4 Cant figure it out
kow [346]
The answer is -12. Do you need to know how I did it?
7 0
4 years ago
The graph (shown in red) below shows the solution set of which inequality?
Elina [12.6K]

Answer:

C

Step-by-step explanation:

The red portion shows all numbers GREATER THAN or EQUAL TO 0.

So that would be x ≥ 0

<em>Looking at the answer choices, there is no "x", rather "√x"</em>

<em>To make it "x", we need to square both sides and the option C wouldn't make a difference. Shown below:</em>

<em>\sqrt{x} >0\\(\sqrt{x} )^2>0^2\\x>0</em>

<em />

<em>Option C is right.</em>

8 0
3 years ago
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