Data:
15 16 14 15 19 17
n=6 points
sum is 96
mean is 96/6 = 16
Now we look at the absolute deviations, each of which is the absolute value of a score minus the mean, basically the distance of the score to the mean .
Scores 15 16 14 15 19 17
AbsDev 1 0 2 1 3 1
The sum of the absolute deviations is 8 and there are six of them so the
Mean Absolute Deviation = 8/6 = 4/3
Answer: 2. 8/6
Answer:
the correct answer is 22 and 12
Step-by-step explanation:
[tex]\begin{gathered} \text{The inequality is,} \\ 5
Let us calculate the area of the walk.
Since the width of the walk is 3 feet, and the walk will be placed all the 4 sides,
Length of the plot including walk = 20 + (2 × 3) = 20 + 6 = 26 feet.
Breadth of the plot including walk = 30 + (2 × 3) = 36 feet.
Area of the plot including walk = 26 × 36 square feet.
Area of the plot = 20 × 30 square feet.
Area of the walk = (26 × 36) - (20 × 30)
= 936 - 600
= 336 square feet.
=
square yards
= 37.3 square yards
Cost of the walk per square yard = $12.25.
Therefore, total cost of the walk = 12.25 × 37.3 = $456.92.
IQR= 18 is the interquartile range of his scores.