The lines on a 2 cup liquid measuring cup divide each cup into eighths. If you measure 1 cups of water, between
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Answer:
We fail to reject the null hypothesis that the average content of containers of the lubricant is 10 liters, this at the significance level of 0.01
Step-by-step explanation:
Let X be the random variable that represents the content of a container of the lubricant. We have observed n = 10 values, = 10.06 and s = 0.2459. We assume that X is normally distributed.
We have the following null and alternative hypothesis
vs
(two-tailed alternative)
We will use the test statistic
because we have a small sample size. And the observed value is
if is true, then T has a t distribution with n-1 = 9 degrees of freedom.
The rejection region for a two-tailed alternative and a significance level of 0.01 is given by RR = {t | t < -3.2498 or t > 3.2498}, where 3.2498 is the value such that there is an area of 0.005 above this number and under the density of the t distribution with 9 df.
Because the observed value 0.7716 does not fall inside RR, we fail to reject the null hypothesis.