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monitta
3 years ago
9

Solve for X. Give me the right answer

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
Five exterior angles of a hexagon are 41° 32°,67º 71°, and 55°, What is the measure of the sixth exterior
angle
Can yo help me w this
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Prove the identity.<br> tan(x − y) + tan(z − x) + tan(y − z) = tan(x − y) tan(z − x) tan(y − z)
Viktor [21]

Step-by-step explanation:

This is known as the triple tangent identity.  Start with the fact that the three angles add up to 0.

(x − y) + (z − x) + (y − z) = 0

Subtract two terms to the other side and take the tangent:

x − y = -((z − x) + (y − z))

tan(x − y) = tan(-((z − x) + (y − z)))

Use reflection property:

tan(x − y) = -tan((z − x) + (y − z))

Now use angle sum identity:

tan(x − y) = -[tan(z − x) + tan(y − z)] / [1 − tan(z − x) tan(y − z)]

tan(x − y) = [tan(z − x) + tan(y − z)] / [tan(z − x) tan(y − z) − 1]

tan(x − y) [tan(z − x) tan(y − z) − 1] = tan(z − x) + tan(y − z)

tan(x − y) tan(z − x) tan(y − z) − tan(x − y) = tan(z − x) + tan(y − z)

tan(x − y) tan(z − x) tan(y − z) = tan(x − y) + tan(z − x) + tan(y − z)

4 0
3 years ago
Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee
Radda [10]
Cosine Law:
c² = a² + b² - 2 a b cos C
Answer:
C ) area of square c² = area of square a² + area of square b²
- area of defect 1 - area of defect 2 
3 0
3 years ago
Read 2 more answers
Solve this inequality algebracially. |3-x|&gt;10
xeze [42]

Answer:

x < -7 or x > 13

Step-by-step explanation:

3 - x < -10 or 3 - x > 10

-x < -13      or    -x > 7

x > 13         or    x < -7

Answer: x < -7 or x > 13

8 0
2 years ago
Read 2 more answers
There are infinitely How many pairs of numbers of which the sum of their cube roots is zero give two of these pairs
ivanzaharov [21]

Answer:

Infinite pairs of numbers

1 and -1

8 and -8

Step-by-step explanation:

Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:

\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y

Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.

Examples: 1 and -1; 8 and -8; 27 and -27.

8 0
3 years ago
Please help!! i’m stuck
eduard

Answer:

17

Step-by-step explanation:

8 0
3 years ago
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