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a_sh-v [17]
3 years ago
6

If you take Coleman's test grade and divide by 2 and add 27, you get 67. Write and solve an equation to find Coleman's test grad

e.
A) 20
B) 47
C) 80
D) 188
Mathematics
2 answers:
alekssr [168]3 years ago
5 0
It's c because. 80 divided. by 2 equals 40 then add 27 that equals 67
Ymorist [56]3 years ago
4 0

Answer: 80


Step-by-step explanation:

Let Coleman's test grade be 'x'.

Then according to the given situation, the required equation will be

\frac{x}{2}+27=67

To solve the equation first subtract 27 from both sides, we get

\Rightarrow\frac{x}{2}=67-27\\\Rightarrow\frac{x}{2}=40

Now, multiply 2 on the both sides, we get

x=80

Hence, Coleman's test grade=80

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3. Solve 2log4y - log4 (5y - 12) = 1/2<br>​
Ilia_Sergeevich [38]

Answer:

y =  4  or y = 6

Step-by-step explanation:

2log4y - log4 (5y - 12) = 1/2

​2log_4(y) - log_4(5y-12) = log_4(2)           apply law of logarithms

log_4(y^2) + log_4(1/(5y-12)) = log_4(/2)    apply law of logarithms

log_4(y^2/(5y-12)) = log_4(2)                     remove logarithm

y^2/(5y-12) = 2                                            cross multiply

y^2 = 10y-24                                                  rearrange and factor

y^2 - 10y + 24 = 0

(y-4)(y-6) = 0

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4 0
3 years ago
3. The area of a rectangular deck, in square meters, is given by the polynomial 40p2 + 24p.
lorasvet [3.4K]

Answer:

Length = 5p + 3

Perimeter = 26p + 6

Step-by-step explanation:

Given

Area = 40p² + 24p

Width = 8p

Solving for the length of deck

Given that the deck is rectangular in shape.

The area will be calculated as thus;

Area = Length * Width

Substitute 40p² + 24p and 8p for Area and Width respectively

The formula becomes

40p² + 24p = Length * 8p

Factorize both sides

p(40p + 24) = Length * 8 * p

Divide both sides by P

40p + 24 = Length * 8

Factorize both sides, again

8(5p + 3) = Length * 8

Multiply both sides by ⅛

⅛ * 8(5p + 3) = Length * 8 * ⅛

5p + 3 = Length

Length = 5p + 3

Solving for the perimeter of the deck

The perimeter of the deck is calculated as thus

Perimeter = 2(Length + Width)

Substitute 5p + 3 and 8p for Length and Width, respectively.

Perimeter = 2(5p + 3 + 8p)

Perimeter = 2(5p + 8p + 3)

Perimeter = 2(13p + 3)

Open bracket

Perimeter = 2 * 13p + 2 * 3

Perimeter = 26p + 6

4 0
4 years ago
What is an end point of a ray
Slav-nsk [51]

Answer:

The end point of a ray is A

Step-by-step explanation:

Hope this Helps

5 0
3 years ago
There are 12 students in a graduate class. The students are to be divided into three groups of 3, 4, and 5 members for a class p
exis [7]

Answer:

27720

Step-by-step explanation:

Given that there are 12 students in a graduate class. The students are to be divided into three groups of 3, 4, and 5 members for a class project.

From 12 students 3 students for group I can be selected in 12C3 ways.

Now from remaining 9, 4 students can be selected for II group in 9C4 ways

The remaining 5 have to be placed in III group.

Hence possible divisions for grouping the 12 students in the class into three groups

= 12C3 *9C4

= =220*126=27720

8 0
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astra-53 [7]
The answer is B. 91.44
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3 years ago
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