Answer:Perimeter of a rectangle is 2*the length plus 2*the width
P = 2L + 2W and P = 130, so
L + W = 65
Three times the length is equal to 10 times the width, giving
3L = 10W
Substituting into the above for L = 65 – W,
3(65 – W) = 10W
195 – 3W = 10W
195 = 13W
W = 195/13 = 15
W = 15 yards,
And L = (10/3)W = (10/3)*15 = 50
L = 50 yards
Step-by-step explanation:
Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean 
and a standard deviation 
. For a value x we compute the z-score as 
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
Volume of a hemisphere is 2/3•pi•r^3
The answer is 56.5m^3
2m is what I got definitely unsure though
.0018529956763434 is my calculated answer.<span />
