PLEASE HELP!! What is the scale factor?

A farmer is tracking the number of soybeans his land is yielding each year. He finds that the function f(x) = −x2 + 20x + 100 mo

labwork [276]

Answer:

The farmer should expect to LOSE 10 pounds of soybeans per acre per year

Step-by-step explanation:

f(x)=-x^2 + 20x + 100

just find how many soybeans his land will yield (per acre) after 10 and 20 years:

After 10: 200 pounds of soybeans/acre

After 20: 100 pounds of soybeans/acre

Because 10 years have passed and they lost 100 pounds of soybean production per acre, the farmer should expect to lose 10 pounds of soybeans per acre per year (-10 pounds of soybeans per acre/year)

3 0

3 years ago

Jason and Jill or two students in mr. White's math class. On the last 5 quizzes Jason scored an 80 90 95 85 and 70. Jill scored

Mrac [35]

Jason's scores : 80 90 95 85 70 and

Jill's score : 70 75 90 100 95.

Mean of Jason's scores = $\frac{80 + 90 + 95 + 85 + 70}{5}=\frac{420}{5}=84.$

Mean of Jill's scores = $\frac{70+75+90+100+95}{5}=\frac{430}{5}=86$

Now, in order to find the mean absolute deviation, need to find the difference of each score from means.

Mean absolute deviation for Jason's scores.

|84-80| = 4

|84-90| = 6

|84-95| = 9

|84-85| = 1

|84-70|= 14

$\frac{4+6+9+1+14}{5}=\frac{34}{5}=6.8$

Mean absolute deviation for Jill's scores

|86-70| = 16

|86-75| = 11

|86-90| = 4

|86-100| = 14

|86-95|= 9

$\frac{16+11+4+14+9}{5}=\frac{54}{5}=10.8$

Jill got average quiz score 86 and Jason got 84.

Therefore, Jill got better quiz average.

Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.

Therefore, Jason got more consistent grades.

8 0

3 years ago

Melissa wrote an expression equivalent to the one shown. 4x + 8x + 7 + 4.which could be the expression Larisa wrote?

Ivan

Answer:

B 12x+11

Step-by-step explanation:

4x + 8x + 7 + 4

Combine like terms

12x +11

4 0

2 years ago

A bag contains 40 coins, all of them are either 2 cent or 5 cent coins. If the value of the money in the bag is $1.55, find the

dlinn [17]

Answer: Explanation:First, let's call the number of 2 cent coins: tNext, let's call the number of 5 cent coins: fWe can then write to equations from the information in the problem.Equation 1: t+f=40Equation 2: 0.02t+0.05f=1.55Step 1) Solve the first equation for t:t+f=40t+f−f=40−ft+0=40−ft=40−fStep 2) Substitute (40−f) for t in the second equation and solve for f:0.02t+0.05f=1.55 becomes:0.02(40−f)+0.05f=1.55(0.02×40)−(0.02×f)+0.05f=1.550.80−0.02f+0.05f=1.550.80+(−0.02+0.05)f=1.550.80+0.03f=1.550.80−0.80+0.03f=1.55−0.800+0.03f=0.750.03f=0.750.03f0.03=0.750.030.03f0.03=25f=25Step 3) Substitute 25 for f in the solution to the first equation at the end of Step 1 and calculate t:t=40−f becomes:t=40−25t=15The Solution Is:There are:15 two cent coins25 five cent coins

Step-by-step explanation:

5 0

2 years ago

a rectangle has a length of 15 inches less than 5 times it’s width. If the area of the rectangle is 2750 square inches. what is

irakobra [83]

let L = length and let W = width.

Use the equations 2L + 2W = 2750

and L = 5W + 15

Then do the steps as follows -

1. Plug the equation for what L equals into the first equation

2(5W+15) + 2W = 2750

2. Then distribute the 2

10W + 30 + 2W = 2750

3. Then add like terms

12W + 30 = 2750

4. Then subtract 30 from both sides

12W = 2720

5. Divide by 12 on both sides

W = 226.67

6. Then plug that into the second equation

L = 5(226.67) + 15

L = 1148.35 should be the answer

4 0

2 years ago