(50 points plz help asap)

Mathematics

1 answer:

vesna_86 [32]3 years ago

5 0

Step-by-step explanation:

Molecular signaling includes the molecules which perform by transmitting information between cells in the body. However the molecular characteristics of signaling molecules can differ highly. Some the molecules transmit signals for a short distance however some of them carry over long distances.

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Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

$n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3$

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }$

The critical value of <em>t</em> is:

$\alpha /2=0.05/2=0.025$

degrees of freedom $=n_{1}+n_{2}-2=200+200-2=398$

$t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96$

Compute the 95% confidence interval for the difference between two mean as follows:

$CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)$

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0

3 years ago

The force (F) needed to cause the acceleration (a) of an object of mass, m, is given by the equation, F=ma where m is the object

KATRIN_1 [288]

From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;

F = ma

In this case, m = 5kg, a = 6m/s^2 and we want to find F

F = 5 x 6

F = 30N

Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.

8 0