What is the scale of the number 280?

A line has a slope of 1 over 4 and passes through the point 0.2 4 over 5 find the value of b , the y intercept

Finger [1]

Answer:

it equals 7

Step-by-step explanation:

7 0

3 years ago

How to do this question by proving the identity?

jeyben [28]

$\sin^3 \theta-\cos^3 \theta=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin^2 \theta+\sin \theta\cos \theta +\cos^2 \theta)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\
(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)=(\sin \theta-\cos \theta)(\sin \theta\cos \theta+1)\\\\$

6 0

4 years ago

The answer is not A or B

Nat2105 [25]

Answer:

C) 4

Step-by-step explanation:

Arcs on one side of the diameter adds upto 180°.

Therefore,

$(2 + 17x) \degree + 54 \degree + 56 \degree = 180 \degree \\ \\ (2 + 17x) \degree + 110 \degree = 180 \degree \\ \\ (2+ 17x) \degree = 180 \degree - 110 \degree\\ \\ (2 + 17x) \degree = 70 \degree \\ \\ 2 + 17x = 70 \\ 17x = 70 - 2 \\ \\ x = \frac{68}{17} \\ \\ x = 4$

4 0

3 years ago

Read 2 more answers

In parallelogram QRST QS RT Is QRST a rectangle ?

fomenos

Answer:

The correct option is A.

Step-by-step explanation:

It is given that the QRST is a parallelogram and the diagonals QS and RT are congruent.

According to the property of parallelogram if the length of diagonals are same, then the parallelogram is rectangle. We can also prove it.

Let QRST be an parallelogram and QS=RT.

In triangles QRT and RQS.

$RT=QS$ (Diagonals)

$QR=QR$ (Common side)

$QT=RS$ (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QRT and triangle RQS are congruent.

By CPCT,

$\angle R=\angle Q$

Since the sum of two consecutive angles of a parallelogram is 180 degree.

$\angle R+\angle Q=180$

$2\angle R=180$

$\angle R=90$

Therefore the measure of angle R and angle Q are 90 degree.

Similarly in triangle QST and RTS,

$RT=QS$ (Diagonals)

$ST=ST$ (Common side)

$QT=RS$ (Opposite sides of the parallelogram are same)

So by SSS rule of congruence, triangle QST and RTS are congruent.

By CPCT,

$\angle S=\angle T$

Since the sum of two consecutive angles of a parallelogram is 180 degree.

Therefore the measure of angle S and angle T are 90 degree.

Since the measure of all interior angles of QRST are 90 degree, therefore the parallelogram QRST is a rectangle.

6 0

4 years ago

Read 2 more answers

What is the value of x ?

zimovet [89]

Each angle of the triangle added together must be equal to 180, so 53+45=98. 180-98=82. So the top angle is 82, the value of x has to be equal to 180-82 which equals 98

8 0

3 years ago