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3 years ago

How do you use repeat subtraction to determine 4 divided by 2/5.

Mathematics

1 answer:

kolezko [41]3 years ago

3 0

2×2 because 4 so do 2×2 then get 4 and you remander will be 1

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telo118 [61]

ANSWER

The correct answer is C

EXPLANATION

We want to find the quotient:

$- \frac{10}{19} \div ( - \frac{5}{7} )$

We multiply by the reciprocal of the second fraction:

$- \frac{10}{19} \times ( - \frac{7}{5} )$

We cancel out the common factors to obtain:

$- \frac{2}{19} \times ( - \frac{7}{1} )$

We multiply to get

$\frac{ - 2 \times - 7}{19 \times 1}$

This simplifies to :

$\frac{14}{19}$

The correct answer is C

7 0

3 years ago

Read 2 more answers

Which expressions are equivalent to -f-5(2f-3)

gizmo_the_mogwai [7]

Answer:

-11f +15

Step-by-step explanation:

-f-5(2f-3)

Distribute

-f -10f +15

Combine like terms

-11f +15

3 0

3 years ago

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PLS HELP 25 POINTS NO CAP PLS BRAINLEIST

Oliga [24]

Answer:

I can't see the picture or handwriting

7 0

3 years ago

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I need someone to help me with this question?

-Dominant- [34]

AAB I think that's it get back to me If its wrong

6 0

3 years ago

2.The mean area of several thousand apartments in a new development is advertised to be 1,100 square feet. A consumer advocate h

KiRa [710]

Answer:

Null Hypothesis, $H_0$ : $\mu$ = 1,100 square feet

Alternate Hypothesis, $H_A$ : $\mu$ < 1,100 square feet

Step-by-step explanation:

We are given that the mean area of several thousand apartments in a new development is advertised to be 1,100 square feet.

A consumer advocate has received numerous complaints that the apartments are smaller than advertised.

Let $\mu$ = mean area of several apartments.

So, Null Hypothesis, $H_0$ : $\mu$ = 1,100 square feet

Alternate Hypothesis, $H_A$ : $\mu$ < 1,100 square feet

Here, null hypothesis states that the mean area of apartments are same as advertised.

On the other hand, alternate hypothesis states that the mean area of apartments are smaller than advertised.

So, this would be the appropriate null and the alternative hypothesis to test this claim.

4 0

3 years ago