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Nadusha1986 [10]
3 years ago
13

Find the point (x1,x2) that lies on the line x1 +5x2 =7 and on the line x1 - 2x2 = -2.

Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Given :

Two equation x_1 +5x_2 =7 and x_1 - 2x_2 = -2 .

To Find :

The point of intersection of these lines .

Solution :

We will use elimination method :

From equation 1 :

x_1=7-5x_2

Putting value of x_1 in equation 2 we get :

(7-5x_2)-2x_2=-2\\\\7-7x_2=-2\\\\x_2=\dfrac{9}{7}

Putting value of x_2 in equation 1 we get :

x_1+5\times \dfrac{9}{7}=7\\\\x_1=\dfrac{4}{7}

Therefore , point of interaction is (\dfrac{4}{7},\dfrac{9}{7}) .

Hence , this is the required solution .

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A student says that the x-intercept of the graph of × + 2y =5 is the point (0,5). Is the student correct or incorrect? Explain y
ivanzaharov [21]

The student is incorrect, the actual x-intercept is (5, 0).

<h3>Is the student correct or incorrect?</h3>

Here we have the equation:

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The student says that the x-intercept is the point (0, 5).

So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).

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5 0
2 years ago
FInd the value of C.
My name is Ann [436]

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The side C equals to 10. hence the answer is letter A

Step-by-step explanation:

To solve this, we need to use trigonometric functions.

we know that sin (α) = Lo / H for a triangle. Being Lo : Length of the opposite side and H: Length of the hypotenuse.

Given α= 45º and Lo= 5√2 and replacing in the equation:

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Using trigonometric identities we know that sin(45º) =(√2)/2. Replacing in equation (1):

sin (45º) = (√2)/2 = 5√2 / C ⇒ C = 2 *5 *√2 / (√2) ⇒ C=10

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If RT is greater than BA, which correctly compares c and s
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Answer:


Step-by-step explanation:

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