This was really useful in determining one's location during the times when technology wasn't that advanced yet. First is that it depends as to what time of the day is it being used. If used at day, most probably at high noon, the altitude of the sun would be measured and recorded and/or remembered. Most of the times, the latitude is determined during the day since it is much easier. At night, a star of known declination will be substituted to the sun. Most of the times, the North Star is used. Then, an almanac will be utilized to determine the declination of the Sun or the star, depending on which was used. After which, the formula is applied, which is latitude = 90 degrees - measured altitude +declination.
Answer:
The correct answer to the following question is option "b".
Explanation:
The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).
- In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
- In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".
That's why the option "b" is correct.
Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.
I would vote for D since you can adjust picture positioning and wrapping. A is BS, B and C are not true.
I’m sorry I do not speak that
