All categories

3 years ago

Solve each system by the addition method.

Mathematics

1 answer:

bagirrra123 [75]3 years ago

6 0

Answer:

(x, y) = (2, -1.5)

Step-by-step explanation:

x + 2y = -1

5x - 4y = 16

<=>

(2)x + (2)2y = (2)(-1)

5x - 4y = 16

<=>

2x + 4y = -2

5x - 4y = 16

<=>

7x = 14

<=>

x = 2

(*)x + 2y = -1

=> 2 + 2y = -1

=> 2y = -3

=> y = -1.5

=> (x, y) = (2, -1.5)

You might be interested in

Barbara is a research biologist for Green Carpet Lawns. She is studying the effects of fertilizer type, temperature at time of a

slega [8]

Answer: 90

Step-by-step explanation:

Given : The number of fertilizer types = 6

The number of temperature zones =5

The number of water treatments=3

The number of different lawn plots = $6\times5\times3=90$

Hence, the number of different lawn plots she needs in order to test each fertilizer type, temperature range, and water treatment configuration =90

5 0

3 years ago

Read 2 more answers

What is the correct sum of 2.34 and 128.8

jekas [21]

Answer:

131.14

Step-by-step explanation:

Hope this helps!! Good luck!!

6 0

4 years ago

Read 2 more answers

If x5 = y3, then x = ?

mel-nik [20]

Answer: Your answer would be x = y^3/5

Hope this helped

8 0

3 years ago

The original price for a jacket was 124.95. It is on sale for 20% off. Witch of the following gives the best estimate of the sav

d1i1m1o1n [39]

20% of 124.95 is close to $125 so that is equal of 12.50 of 10% so multiply by 2 which is $25.00 so the estimate discount of the jacket will be $25.00

7 0

3 years ago

Read 2 more answers

how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

PIT_PIT [208]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589$

3 0

3 years ago