Z-scores are expressed in terms of standard deviations from their means. <span>The standard score is simply the score, minus the mean score, divided by the standard deviation. It is calculated as follows:
z = X- mean / standard deviation
z = 2.7 - 2.4 / 1.5
z = 0.2</span>
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1)
∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰
AB = 370 m
AC = 510 m
To find BC we can use cosine law.
a² = b² + c² -2bc*cos A
|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)
|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =
|BC| ≈ 553 m
2)
To find ∠ACB, we are going to use law of sine.
sin(∠BAC)/|BC| = sin(∠ACB)/|AB|
sin(76⁰)/553 m = sin(∠ACB)/370 m
sin(∠ACB)=(370*sin(76⁰))/553 =0.6492
∠ACB = 40.48⁰≈ 40⁰
3)
∠BAC = 76⁰
∠ACB = 40⁰
∠CBA = 180-(76+40) = 64⁰
Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰
4)
Shortest distance from A to BC is height (h) from A to BC.
We know that area of the triangle
A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).
Also, area the same triangle
A= (1/2)|BC|*h = (1/2)*553*h.
So, we can write
(1/2)*370*510*sin(76⁰) =(1/2)*553*h
370*510*sin(76⁰) =553*h
h= 370*510*sin(76⁰) / 553= 331 m
h=331 m
Answer:
who will answer??
Step-by-step explanation:
<h3>
Answer:</h3>
<u>It squares the amount you scaled it by.</u>
<h3>
Step-by-step explanation:</h3>
For example, imagine that you had 2 by 2 square, and then you put it through a scale factor of 2.
Now each side length would be double of what it once was.
But when you multiply the new lengths together, the area would be of 4 times more.
(Original Equation) 2 * 2 = 4
(Scale Factor of 2) 4 * 4 = 16
So when the scale factor is made, the area would be squared to the multiple that you scaled it by.
<em>***A square root is a number times itself.</em>
<em>(eg): 3 * 3 = </em><em>9</em>
<em> 15 * 15 = </em><em>225</em>
<em>9 and 225 would be the square root in these problems.</em>