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Alex73 [517]
3 years ago
11

3t^2+10t+7 factor im confused what im doing

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

(3t + 7) (t + 1)

Step-by-step explanation:

3t^2 + 10t + 7

(3t^2 + 3t) (7t+7)

3t (t+1) 7 (t+1)

(3t+7) (t+1)

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The sum of 4 consecutive even integers is -12. find the largest integer.
Ipatiy [6.2K]

Answer:

The largest even integer is 0

Step-by-step explanation:

Given as :

The sum of four consecutive even number = - 12

Let The first even number = 2 x

The second even number = (2 x + 2)

The third even number = (2 x + 4)

The fourth even number = (2 x + 6)

<u>According to question</u>

sum of four consecutive even number = - 12

Or, 2 x + (2 x + 2) + (2 x + 4) + (2 x + 6) = - 12

Or, (2 x + 2 x + 2 x + 2 x) + (2 + 4 + 6) = - 12

Or, 8 x + 12 = - 12

Or, 8 x = - 12 - 12

Or, 8 x = - 24

∴  x = \frac{- 24}{8}

i.e  x = - 3

now, putting the value of x

The first even number = 2 × - 3 = - 6

The second even number = (2 × - 3 + 2) = - 6 + 2 = - 4

The third even number = (2 × - 3 + 4) = - 6 + 4 = - 2

The fourth even number = (2 × - 3 + 6) = - 6 + 6 = 0

So, The largest even integer = 0

Hence, The largest even integer is 0  Answer

6 0
3 years ago
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