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stellarik [79]
3 years ago
7

4( x - 3 ) - 5x ≥ -1 Can someone solve for this plz ?

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

Step-by-step explanation:

4x - 12 - 5x ≥ -1

-x - 12 ≥ -1

-x ≥ 11

x ≤ -11

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i jave a 5 in my ones place. the digit in my tens place os 3 plus the digit in my ones place. the digit in my hundreds place is
KatRina [158]

Answer:

The number is 385.

Step-by-step explanation:

The 5 is in the ones place so you put that at the end. The digit in the tens place is 3 plus the digit in the ones place which is 5 so 3 + 5 = 8 so the 8 is in the tens place. The digit in the hundreds place is 2 less than the digit in the ones place which is 5 so 5 - 2 = 3 so the 3 is in the hundreds place

4 0
3 years ago
Solve for a: 3a - 5(a - 2) = 34<br><br>A: a=1<br>b: a=-12<br>c: a=-22<br>d: a=0 ​
nalin [4]

Answer:

b. a=-12

Step-by-step explanation:

3a-5a+10=34

multiply -5 times a and -2

-2a+10=34

-5a from 3a

-2a=24

subtract 10 from both sides

a=-12

-2a divided by both sides

8 0
3 years ago
Read 2 more answers
Pls help me with geometry
zmey [24]

Answer:

x = 20

y = 73

Step-by-step explanation:

8x - 87 + 7x - 33 = 180

15x = 180 + 87 + 33

15x = 300

x = 20

8x - 87 = y

160 - 87 = y

y = 73

5 0
3 years ago
every evening jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she
Darya [45]
Let Q= the number of quarters and D= the number of dimes.
Q+D= 40 coins
0.25Q+0.1D= $7.75
Rewrite equation 1 as: D = 40-Q and substitute into equation 2
0.25Q+0.1(40-Q)= 7.75 Simplify the left side
0.25Q+4-0.1Q= 7.75 Subtract 4 from both sides
0.25Q-0.1Q= 3.75 Convime like terms on left side
0.15Q= 7.75 Divide both sides by 0.15
Q=25 and D= 40-Q
D= 40-25 which is 15
So Jenna had 25 quarters and 15 dimes.
<span>To check multiply 25 x 25 and 15x10 which equals 625 and 150 this equals 775 so this is 7.75</span>
8 0
3 years ago
Can you guys help me out please
garri49 [273]

no l am not help you do you understand d

7 0
3 years ago
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