Answer: -4,3
Step-by-step explanation: When you find slope of two points you do the change of y over x. Which basically means you subtract x and subtract y. Both values. -10-(-6) 10-7. -4,3.
Answer:
0.016062.
Step-by-step explanation:
Assume that the population is normal:
~(,
2
) = (1185, 702
).
Then the distribution of the sample mean
̅ =
1 + 2 + 3 + ⋯ + 100
100
is exactly normal with mean
̅= (̅) = = 1185 hours
and standard deviation
̅= (̅) =
√
=
70
√100
= 7 hours.
The standardized variable
=
̅ − ̅
̅
=
̅ − 1185
7
Is distributed as (0,1).
The following value of corresponds to the value ̅= 1200 of ̅:
=
̅−̅
̅
=
1200−1185
7
= 2.142857.
Therefore,
(̅ ≥ 1200) = (
̅ − ̅
̅
≥
1200 − ̅
̅
) = ( ≥
1200 − 1185
7
) = ( ≥ 2.142857) =
= 1 − ( < 2.142857) = 1 − 0.983938 = 0.016062,
because using the command
= NORM. S.DIST(2,142857; TRUE)
from Microsoft Excel we can see that
= 2.142857
gives
( < 2.142857) = 0.983938.
Only rarely, just over one time in a hundred tries of 100 light bulbs, would the average life exceed 1200 hours
Answer: 3
Step-by-step explanation:
7x=21 21/7=3
Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
Answer:
(-4, -3), (4, -1), (8, 0), (12, 1)
Step-by-step explanation:
The x- and corresponding y-values are listed in the table. Put each pair in parentheses, <em>x-value first</em>. (That is an <em>ordered pair</em>.)
(x, y) = (-4, -3) . . . . from the first table entry
(x, y) = (4, -1) . . . . from the second table entry
(x, y) = (8, 0) . . . . from the third table entry
(x, y) = (12, 1) . . . . from the last table entry
