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rewona [7]
4 years ago
10

Identify the functions below as belonging to one of these radio transmission devices: oscillator, transmitting antenna, micropho

ne, or modulator.
a.Sends out radio waves having the same frequency as the current supplied by the oscillator.
b. Enables the waves produced by the antenna to “carry” the pattern of the sound waves picked up by the microphone.
c. Converts a direct current into a high-frequency alternating current.
d. Picks up sound waves and converts them into suitable electric current with the same pattern as the sound waves.
Physics
1 answer:
Katena32 [7]4 years ago
6 0

Answer:

Conditions that result in the emission of electrons from a conductor:

Heating the conductor to a suitable temperature

Exposing the conductor to a strong light

Subjecting the conductor to a very high applied voltage

Subjecting the conductor to high-speed electrons from another source

Both diodes and triodes influence current flow and contain electrodes. Diodes involve only two active pieces; triodes contain three electrodes within a tube. Current can flow through a diode in only one direction. Diodes tend to act as rectifiers. In a triode, the third electrode is a grid located between the cathode and the anode. A small difference of potential between the grid and the cathode controls the number of electrons that reach the anode. Adjusting the charge on the grid affects the number of electrons that can reach the anode. Triodes tend to act as amplifiers.

Transmitting antenna

Modulator

Oscillator

Microphone

RF amplifier

Receiving antenna

Loudspeaker

Demodulator

Tuner

hue, saturation, intensity/brightness

red, blue, green

Explanation:

Penn Foster

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A hockey puck attached to a horizontal spring oscillates on a frictionless, horizontal surface. The spring has force constant 4.
bekas [8.4K]

Answer:

m = 0.164 kg

Explanation:

T (period)

k (force/spring constant)

m (mass)

T = 2*Pi*sqrt(m/k)

T/(2*Pi) = sqrt(m)/sqrt(k)

(T/(2*Pi))*sqrt(k) = sqrt(m)

m = ((T/(2*Pi))*sqrt(k))^2

m = 4.5*((1.2/(2*Pi)))^2

m = 0.1641403175

3 0
3 years ago
A copper wire 225m long must experience a voltage drop of less than 2.0v when a current of 3.5 a passes through it. compute the
MA_775_DIABLO [31]

Answer:

V = I * R

R = 2 / 3.5 = .571 ohms     maximum resistance of wire

R = ρ L / A  where R is proportional to L and inversely proportional to A

A = ρ L / R     minimum area of wire

ρ = 1 / μ  =     1.67E-8 ohm-m      resistivity inverse of conductivity

A = 1.67E-8 ohm-m * 225 m / .571 ohm = 6.68E-6 m^2

A = 6.68 mm^2       since 1 mm^2 = 10-6 m^2   or 1 mm = 10-3 m

A = Π r^2 = 6.68 mm^2

r = (6.68 / 3.14)^1/2 mm = 2.13 mm      radius of wire

d = 2 * r = 4.26 mm

5 0
2 years ago
A car is travelling at 20m/s, accelerates at 4m/s2 . Calculate its velocity after 5s?
IgorLugansk [536]

Answer:

<u>40 m/s</u>

Explanation:

The final velocity of an object that experiences a period of acceleration is given by:

v - vi = A*t

Initial velocity, vi, is = 20m/s

Acceleration, A, is 4m/2^2

Time, t, is 5 seconds

v - vi = A*t

v - 20m/s = (4m/2^2)/(5 sec)

v = (20 m/s) + (20 m/s)

v = 40 m/s

5 0
2 years ago
Which statement describes the force diagram?
Jlenok [28]

Answer: The forces are balanced.

5 0
3 years ago
Why doesn't a radio operating with two batteries function when one of the batteries is reversed? ​
bulgar [2K]

Answer:

If you have two batteries and they have precisely the same voltage then placing one backwards will effectively cancel out the voltages and no current will flow. However, batteries aren't like that. The slightest difference in voltages mean that current will flow.

Explanation:

8 0
3 years ago
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