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rewona [7]
4 years ago
10

Identify the functions below as belonging to one of these radio transmission devices: oscillator, transmitting antenna, micropho

ne, or modulator.
a.Sends out radio waves having the same frequency as the current supplied by the oscillator.
b. Enables the waves produced by the antenna to “carry” the pattern of the sound waves picked up by the microphone.
c. Converts a direct current into a high-frequency alternating current.
d. Picks up sound waves and converts them into suitable electric current with the same pattern as the sound waves.
Physics
1 answer:
Katena32 [7]4 years ago
6 0

Answer:

Conditions that result in the emission of electrons from a conductor:

Heating the conductor to a suitable temperature

Exposing the conductor to a strong light

Subjecting the conductor to a very high applied voltage

Subjecting the conductor to high-speed electrons from another source

Both diodes and triodes influence current flow and contain electrodes. Diodes involve only two active pieces; triodes contain three electrodes within a tube. Current can flow through a diode in only one direction. Diodes tend to act as rectifiers. In a triode, the third electrode is a grid located between the cathode and the anode. A small difference of potential between the grid and the cathode controls the number of electrons that reach the anode. Adjusting the charge on the grid affects the number of electrons that can reach the anode. Triodes tend to act as amplifiers.

Transmitting antenna

Modulator

Oscillator

Microphone

RF amplifier

Receiving antenna

Loudspeaker

Demodulator

Tuner

hue, saturation, intensity/brightness

red, blue, green

Explanation:

Penn Foster

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Why are choir concerts better in performance halls than in gymnasiums?
dlinn [17]

Constructive interference in performance halls and the elimination of echoes are reasons why choir concerts better in performance halls than in gymnasiums.

<h3>What is constructive interference?</h3>

Constructive interference is a phenomenon which occurs when two waves travelling in same direction and which are in phase add up together to produce a wave of greater amplitude.

Constructive interference occurs in performance halls while destructive interference occurs in gymnasiums.

Also in performance halls, echoes are minimized due to the padded walls and the curtains while echoes which disturb choir concerts occur in gymnasiums.

Therefore, choir concerts better in performance halls than in gymnasiums because of constructive interference in performance halls and the elimination of echoes.

Learn more about constructive interference and echoes at: https://brainly.in/question/2378717

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2 years ago
Density is ___ per unit volume <br><br> Length <br><br> Area<br><br> Space <br><br> Mass
NARA [144]
Density is Mass per unit volume
5 0
3 years ago
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Please help!!
pantera1 [17]

Answer:

(a) The time the ball stays in the air is approximately 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters

(c) The maximum altitude of the ball is approximately 26.62 m

Explanation:

The given parameters of the question are;

The initial velocity at which a baseball cannon fires balls, u = 29 m/s

The angle at which the cannon is tilted, θ = 52°

(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;

2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}

Where;

t = The time it takes the baseball to reach maximum height

2·t = The total time of flight = The time the ball stays in the air

θ = The angle at which the ball is tilted = 52°

g = The acceleration due to gravity ≈ 9.81 m/s²

u = The initial velocity = 29 m/s

Therefore, we have;

2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s

The time the ball stays in the air, 2·t ≈ 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;

Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}

∴ The distance from the cannon at which the ball will hit the ground = R

Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m

The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters

(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;

H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}

Therefore, we have;

H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m

The maximum altitude of the ball ≈ 26.62 m

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3 years ago
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grin007 [14]

Answer:

when an object is moving

Explanation:

it turns into kinetic energy

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vlada-n [284]
Add the two potential energy
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