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Zielflug [23.3K]
3 years ago
5

A hockey puck attached to a horizontal spring oscillates on a frictionless, horizontal surface. The spring has force constant 4.

50 N/m and the oscillation period is 1.20 s. What is the mass of the puck
Physics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer:

m = 0.164 kg

Explanation:

T (period)

k (force/spring constant)

m (mass)

T = 2*Pi*sqrt(m/k)

T/(2*Pi) = sqrt(m)/sqrt(k)

(T/(2*Pi))*sqrt(k) = sqrt(m)

m = ((T/(2*Pi))*sqrt(k))^2

m = 4.5*((1.2/(2*Pi)))^2

m = 0.1641403175

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When light enters a pair of glasses, it ______________ when it hits the glass
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DetermiOne of the lines in the Balmer series of the hydrogen atom emission spectrum is at 397 nm. It results from a transition f
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Answer:

a)n =7 , b) n = 5

Explanation:

The energy levels of the hydrogen atom is described by the Bohr model

       E_{n} = - 13.606   1/n²

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       E₀ - E_{n} = -13.606 (1/n_{f}² - 1/n₀²)

Let's apply this expression

         n₀ = 2

Let's look for the energy of the different levels and subtract it

n₀          E_{n} (eV)

1            -13,606

2            -3.4015

3           - 1.5118

4           -0.850375

5           -0.54424

6           -0.3779

7           -0.2777

The wavelength of the transition is 397 nm = 397 10⁻⁹ m

The speed of light is related to wavelength and frequency

       c = λ f

The Planck equation gives the energy of a transition

      E = h f

      E = h c /λ

Let's calculate

     E = 6.63 10⁻³⁴ 3 10⁸/397 10⁻⁹

     E = 5.01 10⁻¹⁹ J

Let's reduce to eV

     E = 5.01 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

     E = 3.1313 eV

Let's examine the possible transitions from the initial level ni = 2

     ΔE = E_{2} - E_{n} = -3.1313

     En = 3.13 -3.4015

     E_{n} = 0.2702 eV

When examining the table we see that the level that this energy has is the level of n = 7

Part B      the transition is in the infrared

The frequency is 74 10¹² Hz

We use the Planck equation

       E = h f

       E = 6.63 10⁻³⁴ 74 10¹²

       E = 4.9062 10⁻²⁰ J

       E = 4.9062 10⁻²⁰ / 1.6 10⁻¹⁹

       E = 0.3066 eV

We look for the level with the energy difference

     ΔE = E₄- E_{n} = 0.3066

     E_{n} = 0.3066 - 0.85037

     E_{n} = -0.54376 eV

When examining the table this energy has the level n = 5, therefore from this level the transition occurs

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Answer:

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