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Zielflug [23.3K]
2 years ago
5

A hockey puck attached to a horizontal spring oscillates on a frictionless, horizontal surface. The spring has force constant 4.

50 N/m and the oscillation period is 1.20 s. What is the mass of the puck
Physics
1 answer:
bekas [8.4K]2 years ago
3 0

Answer:

m = 0.164 kg

Explanation:

T (period)

k (force/spring constant)

m (mass)

T = 2*Pi*sqrt(m/k)

T/(2*Pi) = sqrt(m)/sqrt(k)

(T/(2*Pi))*sqrt(k) = sqrt(m)

m = ((T/(2*Pi))*sqrt(k))^2

m = 4.5*((1.2/(2*Pi)))^2

m = 0.1641403175

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2 years ago
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3 years ago
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Leviafan [203]
Assuming Earth's gravity, the formula for the flight of the particle is: 

<span>s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160. </span>

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<span>Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet. </span>
7 0
3 years ago
Read 2 more answers
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