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4 years ago

14

What is physical quantity?

1 answer:

-Dominant- [34]4 years ago

3 0

Explanation:

physical quantity is a property of a material or system that can be quantified by measurement. A physical quantity can be expressed by either a numerical value, the product of a numerical value and a unit or a finite sequence of numerical values and units.

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A moving car has kinetic energy. If it speeds up until it is going four times faster than before, how much kinetic energy does i

Eva8 [605]

<h2>Ratio of final kinetic energy to initial kinetic energy is 16.</h2>

Explanation:

Kinetic energy , KE = 0.5mv²

Here car speeds up to four times the initial speed, we need to find ratio of final kinetic energy to initial kinetic energy.

Final speed = 4 x Initial speed = 4v

Initial KE = 0.5mv²

Final KE = 0.5 x m x (4v)²

Final KE = 16 x 0.5 x m x v²

Final KE = 16 x Initial KE

Ratio of final kinetic energy to initial kinetic energy is 16.

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3 years ago

Why does the arrow labeled F norm point upward?

ohaa [14]

The answer is D I think

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2 years ago

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5. Lady Gaga needed someone to buy more meat for her meat dress. The famous

krok68 [10]

Answer:

she can travel 24000 meters she cant reach the store she can get as much as 125 miles

Explanation:

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3 years ago

A golf ball with an initial angle of 34° lands exactly 240 m down the range on a level course.

g100num [7]

Answer:50.39 m/s,

40.46 m

Explanation:

Given

launch angle $=34^{\circ}$

Range=240 m

We know that Range $=\frac{u^2sin2\theta }{g}$

$240=\frac{u^2sin(68)}{9.81}$

u=50.39 m/s

(b)maximum height of projectile is given by

$H=\frac{u^2sin^2\theta }{2g}$

$H=\frac{50.39^2(sin34)^2}{2\times 9.81}$

H=40.46 m

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4 years ago

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A solid sphere of weight 42.0 N rolls up an incline at an angle of 36.0°. At the bottom of the incline the center of mass of the

Alecsey [184]

Answer:

Part a)

$KE = 77.95 J$

Part b)

$L = 3.16 m$

Part c)

distance L is independent of the mass of the sphere

Explanation:

Part a)

As we know that rotational kinetic energy of the sphere is given as

$KE = \frac{1}{2}I\omega_2 + \frac{1}{2}mv^2$

so we will have

$KE = \frac{1}{2}(\frac{2}{5}mR^2)(\frac{v}{R})^2 + \frac{1}{2}mv^2$

so we will have

$KE = \frac{1}{5} mv^2 + \frac{1}{2}mv^2$

$KE = \frac{7}{10} mv^2$

$KE = \frac{7}{10}(\frac{42}{9.81})(5.10^2)$

$KE = 77.95 J$

Part b)

By mechanical energy conservation law we know that

Work done against gravity = initial kinetic energy of the sphere

So we will have

$mgLsin\theta = KE$

$\frac{42}{9.81}(9.81)L sin36 = 77.95$

$L = 3.16 m$

Part c)

by equation of energy conservation we know that

$\frac{7}{10}mv^2 = mgL sin\theta$

so here we can see that distance L is independent of the mass of the sphere

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3 years ago