Answer: d. 5 m/s^2
Explanation:
Acceleration is the change in velocity in a given time.
a = (30-20)/2 = 5
I think you have them all marked correctly
7. They carry hereditary material from parent
8. 50 percent
1. Nutrition
2. X-linked dominant
If Im wrong Im sorry. its been like 4 years since i took biology but i remember some things
Answer:
16,506 ft²
Explanation:
There are different ways you can divide the area using rectangles and circles. One way is to find the area of the entire width and length, then subtract the empty areas in the corners.
If we take the empty areas and put them together, we find their area is the area of a square minus the area of a circle.
A = (2r)² − πr²
A = 4r² − πr²
A = (4 − π) r²
So the area of the rink is:
A = WL − (4 − π) r²
A = (85)(200) − (4 − π) (24)²
A ≈ 16,506 ft²
I will be making the assumption that you aren't actually really throwing the object over a bridge but rather dropping it as no initial velocity is actually given, which is required to do this problem. This will mean that initial velocity will be zero in this case.
First off, let's state all of the information we are given (the five kinematic quantities)
v₁ = 0 m/s
v₂ = cannot be determined
Δd = ?
Δt = 8 seconds
a (g) = 10 m/s² [down]
Now analyzing what we have, we can determine that we have 3 given quantities, 1 we must solve for, and 1 that cannot be found given our current information.
The five kinematic equations are useful because they all contain four kinematic quantities, and with different combinations too. In this case, we have three (v₁, Δt, a) and have to solve for Δd. The kinematic equation that fits with this would be:
Δd = v₁Δt + 0.5(a)(t)²
We can plug in our given values now.
Δd = 0 m/s(8 s) + 0.5(10 m/s²)(8 s)²
Δd = 0.5(10 m/s²)(8 s)²
Δd = <u>3</u>20 m
Therefore, the total displacement of the object would have to be 300m. (Due to significant digit rules)
Answer:
A. 4d
Explanation:
Magnetic field strength is inversely proportional to distance. So in order to have a smaller magnetic field, we need to move further out from the wire. How far we go exactly can be determined from the formula: B=(μ₀I)/(2πr)
(That is derived from Ampere's Law, which states ∫B•dl=μ₀I)
With that you can set up a ratio between the magnetic fields in both cases. Because the current is the same for both instances, everything reduces out on one side of the equation and leaves you with something that relates the two distances by a ratio of each magnetic field value.
My work is in the attachment, comment for questions.
