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dezoksy [38]
2 years ago
7

A copper wire 225m long must experience a voltage drop of less than 2.0v when a current of 3.5 a passes through it. compute the

minimum diameter of the wire in millimeters (mm) if the electrical conductivity of copper is 60.0 x106 (ohm-m)-1 . answer should be in millimetres and carried out 2 decimal places (x.xx mm)
Physics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

V = I * R

R = 2 / 3.5 = .571 ohms     maximum resistance of wire

R = ρ L / A  where R is proportional to L and inversely proportional to A

A = ρ L / R     minimum area of wire

ρ = 1 / μ  =     1.67E-8 ohm-m      resistivity inverse of conductivity

A = 1.67E-8 ohm-m * 225 m / .571 ohm = 6.68E-6 m^2

A = 6.68 mm^2       since 1 mm^2 = 10-6 m^2   or 1 mm = 10-3 m

A = Π r^2 = 6.68 mm^2

r = (6.68 / 3.14)^1/2 mm = 2.13 mm      radius of wire

d = 2 * r = 4.26 mm

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This won't be easy, because the bat floats in water.  But I think you can get around that little problem like this:

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-- Slip the heavy weight into the tub, slowly.  Some water will run over the top and out of the tub.  That's OK ... it's exactly what you want.  If NO water runs over the top, pour some more in, until it runs out and then stops.  You want the tub full to the brimmy rim with the rock at the bottom of it.

-- Take the heavy weight out of the tub.

-- Now set the tub into a bigger tub or a deep pan.  The next time it overflows and some water runs out of it, you'll need to catch that water and measure it.

-- Get a short piece of heavy string.  Tie the heavy weight to somewhere near the middle of the bat.

-- Slowly slide the bat into the water, with the rock tied to it.  The bat needs to go complete underwater.

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THAT amount is the volume of the bat.

You may have to do some units conversions.  Like if you need the volume of the bat in cm³ and you used measuring vessels marked in fluid ounces.  But you can find all those conversion factors with a search on Floogle.

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3 years ago
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