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Vikentia [17]
3 years ago
9

Complete the square to solve 4x^2 + 24x = 4

Mathematics
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

4x^2+24x=4

Step 1:

make the coefficient of x² as 1, divide both sides by 4

x² +6x =1

Step 2:

take half of coefficient of x, square it and add it to both sides

half of 6 is 3 and 3²=9, so add 9 to both sides

x² +6x+9=1+9

x²+6x+3²=10

(x+3)²=10

now when we take square root we will get both + and - √10 on right side

x+3= +√10

x+3=-√10

solving for x

x=+√10-3

Step-by-step explanation:

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masya89 [10]
Okay. The question is m/9 - 17 = 21. First off, we will add 17 to both sides. -17 + 17 cancels out. 21 + 17 is 38. That leaves m/9 = 38. Multiply each side by 9 to isolate the m, because m is the numerator and 9 is the denominator. m/9 * 9/1 cancels out. 38 * 9 is 342. Let's check this. 342/9 is 38. 38 - 17 is 21. 21 = 21. There. x = 342.
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How much will hi pays in total
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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

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2 years ago
The difference of a number and 8 is no more then 13
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x - 8 = </= 13

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AlladinOne [14]

Answer:A= 1,2 B=1,2 C=-9,10

Step-by-step explanation:

For A=

To find A', reflect the triangle exactly over the y-axis. That will put your A' at (1,2)

For B=

translate the triangle clockwise around the origin, (0,0), to put B' at (1,2)

For C= Translate point C to the left 4, and up 2, so the answer is (-9,10)

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